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alisha [4.7K]
3 years ago
6

Solve the equation. -9x - 15 = 93

Mathematics
2 answers:
belka [17]3 years ago
7 0
X = -12


First is moving the -15 over with the 93 by adding it on both sides. The equation will look like this: -9x = 108
Then you’ll divide by -9 and get x = -12
fomenos3 years ago
4 0
The Answer is X=-12
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What is the point slope equation of a line with slope -5 that contains the point (6,3)
ehidna [41]

Step-by-step explanation:

Given

Slope (m) = -5

Point

(x1 , y1) = ( 6 , 3)

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y - y1 = m ( x - x1)

y - 3 = -5 ( x - 6)

y - 3 = -5x +30

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5x + y - 33= 0

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Hope it will help you :)

3 0
3 years ago
Which expression is equivalent to 3(2x−4)+4x−2
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I hope this helps you



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7 0
3 years ago
What is the length of angle EF in the right triangle below
salantis [7]

Answer:

E.  √180

Step-by-step explanation:

Using Pythagoras' theorem

a^2 + b^2 = c^2 (c = hypotenuse, a and b are legs)

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6 0
4 years ago
For each of the following, state the equation of a perpendicular line that passes through (0, 0). Then using the slope of the ne
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Answer:

The answer is below

Step-by-step explanation:

a) y=3x-1

The standard equation of a line is given by:

y = mx + c

Where m is the slope of the line and c is the intercept on the y axis.

Given that y=3x-1, comparing with the standard equation of a line, the slope (m) = 3, Two lines with slope a and b are perpendicular if the product of their slope is -1 i.e. ab = -1. Let the line perpendicular to y=3x-1 be d, to get the slope of the perpendicular line, we use:

3 × d = -1

d = -1/3

To find the equation of the perpendicular line passing through (0,0), we use:

y-y_1=d(x-x_1)\\d\ is\ the \ slope:\\y-0=-\frac{1}{3} (x-0)\\y=-\frac{1}{3}x

To find  x if the point P(x, 4) lies on the new line, insert y = 4 and find x:

y=-\frac{1}{3}x\\ 4=-\frac{1}{3}x\\-x=12\\x=-12

b) y=1/4 x+2

Given that y=1/4 x+2, comparing with the standard equation of a line, the slope (m) = 1/4. Let the line perpendicular to y=1/4 x+2 be f, to get the slope of the perpendicular line, we use:

1/4 × f = -1

f = -4

To find the equation of the perpendicular line passing through (0,0), we use:

y-y_1=f(x-x_1)\\f\ is\ the \ slope:\\y-0=-4 (x-0)\\y=-4x

To find  x if the point P(x, 4) lies on the new line, insert y = 4 and find x:

y=-4}x\\ 4=-4x\\x=-1

8 0
3 years ago
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