If its to number 9, it's ∈35.48
Answer:
4 ml of the 63% milk drink
Step-by-step explanation:
Multiplying 15 ml by 0.15 results in 2.25 ml, the amount of whole milk in the drink. Let m represent the number of ml of a drink that is 63% milk.
The final amount of milk drink that is to be 45% milk will be 15 ml + m, and the amount of whole milk contained in this drink will be 0.45(15 + m).
Then:
0.15(15 ml) + 0.63(m) = 0.45(15 + m), where m is to be in milliliters.
2.25 + 0.63m = 6.75 + 0.45m
First: consolidate the m terms on the left. 0.63m less 0.45m yields 18 m; then we have:
2.25 + 18m = 6.75, or
18 m = 4.50, or m = 4 ml.
In conclusion: adding 4 ml of that 63% milk drink to the initial 15 ml of 15% milk will result in (15 ml + 4 ml) of a 45% milk drink.
Answer:
yeah
Step-by-step explanation:
Answer
Median bisects the line.
D≡(
2
−3+5
,
2
−9−8
)≡(1,
2
−17
)
E≡(−
2
1+5
,
2
6−8
)≡(2,−1)
F≡(−
2
1−3
,
2
6−9
)≡(−2,
2
−3
)
∴ equation of AD:(y−y
1
)=(
x
2
−x
1
y
2
−y
1
)
AD
(x−x
1
)
⇒(y−6)=
⎝
⎜
⎜
⎛
1+1
2
−17
−6
⎠
⎟
⎟
⎞
(x+1)⇒(y−6)=−
4
29
(x+1)
⇒
4
29
x+y−6+
4
29
=0
AD⇒29x+4y+5=0
equation of BE:(y+9)=(−
2+3
1+9
)
BE
(x+3)
⇒(y+9)=
5
8
(x+3)⇒5y+45=8x+24
BE⇒8x−5y−21=0
Equation of CF:(y+8)=
⎝
⎜
⎜
⎛
−2−5
−
2
3
+8
⎠
⎟
⎟
⎞
CF
(x−5)
⇒(y+8)=−
14
13
(x−5)⇒14y+112=−13x+65
CF:13x+14y+47=0
