Time = distance/time = 13.5/3 = 4.5 hours
Answer is B
Answer: Hi! All of the answers and work are below. Please double check on your work just to make sure. Hope this helped! :)
Step-by-step explanation:
attached below :)
Answer:
(a) Yes, it does not matter if f is continuous or differentiable; every function satisfies the Mean Value Theorem.
(b) ![c =0.51995](https://tex.z-dn.net/?f=c%20%3D0.51995)
Step-by-step explanation:
Given
![f(x) = e^{-4x};\ [0,2]](https://tex.z-dn.net/?f=f%28x%29%20%3D%20e%5E%7B-4x%7D%3B%5C%20%5B0%2C2%5D)
Solving (a); Does the function satisfy M.V.T on the given interval
We have:
![f(x) = e^{-4x};\ [0,2]](https://tex.z-dn.net/?f=f%28x%29%20%3D%20e%5E%7B-4x%7D%3B%5C%20%5B0%2C2%5D)
The above function is an exponential function, and it is differentiable and continuous everywhere
Solving (b): The value of c
To do this, we use:
![f'(c) = \frac{f(b) - f(a)}{b - a}](https://tex.z-dn.net/?f=f%27%28c%29%20%3D%20%5Cfrac%7Bf%28b%29%20-%20f%28a%29%7D%7Bb%20-%20a%7D)
In this case:
![[a,b] = [0,2]](https://tex.z-dn.net/?f=%5Ba%2Cb%5D%20%3D%20%5B0%2C2%5D)
So, we have:
![f'(c) = \frac{f(2) - f(0)}{2 - 0}](https://tex.z-dn.net/?f=f%27%28c%29%20%3D%20%5Cfrac%7Bf%282%29%20-%20f%280%29%7D%7B2%20-%200%7D)
![f'(c) = \frac{f(2) - f(0)}{2}](https://tex.z-dn.net/?f=f%27%28c%29%20%3D%20%5Cfrac%7Bf%282%29%20-%20f%280%29%7D%7B2%7D)
Calculate f(2) and f(0)
![f(x) = e^{-4x}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20e%5E%7B-4x%7D)
So:
![f(2) = e^{-4*2} = e^{-8} = 0.00033546262](https://tex.z-dn.net/?f=f%282%29%20%3D%20e%5E%7B-4%2A2%7D%20%3D%20e%5E%7B-8%7D%20%3D%200.00033546262)
![f(0) = e^{-4*0} = e^{0} = 1](https://tex.z-dn.net/?f=f%280%29%20%3D%20e%5E%7B-4%2A0%7D%20%3D%20e%5E%7B0%7D%20%3D%201)
This gives:
![f'(c) = \frac{0.00033546262 - 1}{2}](https://tex.z-dn.net/?f=f%27%28c%29%20%3D%20%5Cfrac%7B0.00033546262%20-%201%7D%7B2%7D)
![f'(c) = \frac{-0.99966453738}{2}](https://tex.z-dn.net/?f=f%27%28c%29%20%3D%20%5Cfrac%7B-0.99966453738%7D%7B2%7D)
![f'(c) = -0.4998](https://tex.z-dn.net/?f=f%27%28c%29%20%3D%20-0.4998)
Note that:
![f'(x) = (e^{-4x})'](https://tex.z-dn.net/?f=f%27%28x%29%20%3D%20%28e%5E%7B-4x%7D%29%27)
![f'(x) = -4e^{-4x}](https://tex.z-dn.net/?f=f%27%28x%29%20%3D%20-4e%5E%7B-4x%7D)
This implies that:
![f'(c) = -4e^{-4c}](https://tex.z-dn.net/?f=f%27%28c%29%20%3D%20-4e%5E%7B-4c%7D)
So, we have:
![f'(c) = -0.4998](https://tex.z-dn.net/?f=f%27%28c%29%20%3D%20-0.4998)
![-4e^{-4c} =-0.4998](https://tex.z-dn.net/?f=-4e%5E%7B-4c%7D%20%3D-0.4998)
Divide both sides by -4
![e^{-4c} =\frac{-0.4998}{-4}](https://tex.z-dn.net/?f=e%5E%7B-4c%7D%20%3D%5Cfrac%7B-0.4998%7D%7B-4%7D)
![e^{-4c} =0.12495](https://tex.z-dn.net/?f=e%5E%7B-4c%7D%20%3D0.12495)
Take natural logarithm of both sides
![\ln(e^{-4c}) =\ln(0.12495)](https://tex.z-dn.net/?f=%5Cln%28e%5E%7B-4c%7D%29%20%3D%5Cln%280.12495%29)
![\ln(e^{-4c}) =-2.0798](https://tex.z-dn.net/?f=%5Cln%28e%5E%7B-4c%7D%29%20%3D-2.0798)
Apply law of natural logarithm
![\ln(e^{ax}) =ax](https://tex.z-dn.net/?f=%5Cln%28e%5E%7Bax%7D%29%20%3Dax)
So:
![-4c =-2.0798](https://tex.z-dn.net/?f=-4c%20%3D-2.0798)
Solve for c
![c =\frac{-2.0798}{-4}](https://tex.z-dn.net/?f=c%20%3D%5Cfrac%7B-2.0798%7D%7B-4%7D)
Step-by-step explanation:
error
Polynomial error: You have used illegal character ( = )..
Step by Step Solution
More Icon
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
49-((2+5)*2)=0
STEP
1
:
Equations which are never true:
1.1 Solve : 35 = 0
This equation has no solution.
A a non-zero constant never equals zero.
No solutions found
Answer:
798
Step-by-step explanation:
first you do 40x20=800 then 800-6=794 then 794+4=798