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3 years ago

Which beasbs sababwbs

Mathematics

1 answer:

ser-zykov [4K]3 years ago

4 0

Answer:

Step-by-step explanation:

A is the correct answer because beasbs sababwbs is made out of dahhdm fkri, and with this, beasbs sababwbs is found through puberty, and results in big boi xdksks DFK. Hope that this helps you and have a great day :))

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You have a standard deck of 52 cards. you pick one card and then, with out putting the first card back, you pick a second card.

Diano4ka-milaya [45]

First, find the probability of picking one 9. There are four nines in a deck of 52, so the probability is 4/52, which is 1/13.

The probability of picking a 9 the second time is 1/17, because if a 9 was picked the first time, then there are three 9s left and 51 cards left in total.

To find the probability of both events happening, multiply the individual probabilities together:

(1/13)(1/17)

The probability that both cards picked will be 9s is 1/221.

6 0

3 years ago

Hi please help i’ll give brainliest please

Sedaia [141]

Answer:

y = 4

Step-by-step explanation:

15 x 4 = 60

60 = 60

Therfore, y = 4

3 0

3 years ago

Read 2 more answers

4. Suppose P(A) = 0.48 and P(B) = 0.62. a. Can A and B be mutually exclusive? Why or why not. b. If A and B are independent, the

kenny6666 [7]

Answer:

Step-by-step explanation:

a) Two events A,B are said to be mutually exlusive if any of the following occurs.

- A and B have an empty intersection

- A= B^c and their union is the whole sample space

- P(A intersection B) =0

REcall the following formula

$P(A\cupB ) = P(A)+P(B)-P(A\cap B)$

Note that P(A) + P(B) = 1.1. Since the probability is always a number between 0 and 1, it must happen that $P(A\cap B) >0$ , otherwise, $A\cup B$ would have a probability greater than 1. Hence, A, B are not mutually exclusive.

b) by definition, if two events are indepent, we have that the probability of the intersection is equal to products of their probabilites. Or

$P(A\cap B) = P(A)P(B)$

c) Recall that if we have mutuallly exclusive events A, B, then we have that $P(A\cap B)=0$ , if they were independent, we would have the following

$P(A) P(B) =0$

which necesarilly implies that at least one of the two events has 0 probability. (THis is not the case)

7 0

4 years ago

One positive number is 4 more than twice another. Their product is 198

EastWind [94]

Answer:

$\large \boxed{\sf \ \ 9 \text{ and } 22 \ \ }$

Step-by-step explanation:

Hello,

We can write that, x being the second number

(4 + 2*x) *x = 198

Let's solve this equation.

$(4+2x)x=198\\\\4x+2x^2=198 \\\\\text{*** subtract 198 from both sides ***}\\\\2x^2+4x-198 = 0\\\\\text{*** The product of the zeroes is -198/2=-99=-11*9 and their sum is -4/2=-2 ***}\\\\2x^2+4x-198=2(x-9)(x+11)=0\\\\x=9 \ \ or \ \ x=-11$

We are looking for positive number so the solution is 9.

And the first number is 4 + 2 * 9 = 4 + 18 = 22

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

3 0

3 years ago

Read 2 more answers

3. Show that the expression 3b - 4 + 6(b-9) is equivalent to the expression 9 (b-6) -4. Show your work. ANSWER ASAP PLZZ

sattari [20]

EDITED:

so lets make the question more clear

lets make it like this, if were gonna make 10 = b vv (sorry I meant to say 10, but I said 6 ;-;

3(10) - 4 + 6(10-9) = 30 - 4 + 6 = 26 + 6 = 32

= THIS EQUALS 32

Now lets do 9(b-6) - 4 which will be turned into 9(10-6) - 4 = 36 - 4 = THIS EQUALS 32

MY ANSWER IS YES (DONT ASK ME WHY IM WRITING IN CAPS (((: )

7 0

4 years ago