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4 years ago

I need to know how to do this

Mathematics

2 answers:

mash [69]4 years ago

7 0

Answer: 9/10

Step-by-step explanation: .

Schach [20]4 years ago

5 0

Answer:

yes they are.

Step-by-step explanation:

3/1 ×3/10= 9/10

3×3/10=9/10

3×3=9 then put over the 10.

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Zoe planted a 4-foot oak tree in her backyard. The oak tree is expected to grow by 22 inches each year. If the oak tree grows at

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3 years ago

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A grid with 3 rows and 52 columns is tiled with 78 identical 2x1 dominoes. How many ways can this be done such that exactly two

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3 years ago

Y=x+4 in a verbal situation

Mariulka [41]

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Step-by-step explanation:

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3 years ago

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Lowering powers write in terms of first power of cosine. Cos^6

yaroslaw [1]

The main identity you need is the double angle one for cosine:

$\cos^2x=\dfrac{1+\cos2x}2$

We get

$\cos^6x=(\cos^2x)^3=\left(\dfrac{1+\cos2x}2\right)^3=\dfrac{(1+\cos2x)^3}8$

Expand the numerator to apply the identity again:

$\cos^6x=\dfrac{1+3\cos2x+3\cos^22x+\cos^32x}8$

$\cos^6x=\dfrac{1+3\cos2x+3\left(\frac{1+\cos2(2x)}2\right)+\cos2x\left(\frac{1+\cos2(2x)}2\right)}8$

$\cos^6x=\dfrac{1+3\cos2x+\frac32+\frac32\cos4x+\frac12\cos2x(1+\cos4x)}8$

$\cos^6x=\dfrac5{16}+\dfrac7{16}\cos2x+\dfrac3{16}\cos4x+\dfrac1{16}\cos2x\cos4x$

Finally, make use of the product identity for cosine:

$\cos2x\cos4x=\dfrac{\cos6x+\cos2x}2$

so that ultimately,

$\cos^6x=\dfrac5{16}+\dfrac7{16}\cos2x+\dfrac3{16}\cos4x+\dfrac1{32}\cos2x+\dfrac1{32}\cos6x$

$\cos^6x=\dfrac5{16}+\dfrac{15}{32}\cos2x+\dfrac3{16}\cos4x+\dfrac1{32}\cos6x$

4 0

4 years ago

Jane invested her savings in two investment funds. The amount she invested in Fund A was $6000 less than the amount she invested

Irina18 [472]

Answer:

Jane invested $37,000 in Fund B.

Step-by-step explanation:

Let;

IA = Amount invested in Fund A = $6,000

IB = Amount invested in Fund B = ?

PA = Amount of profit from Fund A = IA * 8% = $6,000 * 8% = $480

PB = Amount of profit from Fund B = IB * 2%

Therefore, we have:

Total profit = PA + PB = $1220 ........................ (1)

Substitute the relevant values into equation (1) and solve for IB, we have:

$480 + (IB * 2%) = $1220

IB * 2% = $1220 - $480

IB * 2% = 740

IB = 740 / 2%

IB = $37,000

Therefor, Jane invested $37,000 in Fund B.

4 0

3 years ago