Answer:
The desired point is thus (-1/2, -5).
Step-by-step explanation:
The x-component of this directed line segment is 2 - (-8), or 10, and the y-component is -7 - (1), or -8. This segment is in Quadrant II, since the x-component is positive and the y-component is negative.
The point of interest is (3/4) of the way in the positive x-direction from x = -8. We can express this symbolically as -8 + (3/4)(10), or -8 + 7.5, or -1/2.
The point of interest is 3/4 of the way in the negative y direction from 1, or:
1 + (3/4)(-8), or 1 - 6, or -5.
The desired point is thus (-1/2, -5).
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Answer:
multiply by 3 and divide by 2 to get 6x -y = 12.
Step-by-step explanation:
A standard form equation has mutually prime integers for coefficients, and the leading one is positive. We can get that here by multiplying by 3 (to eliminate the denominator) and dividing by 2 (to remove that common factor). The result is ...
4(3/2)x -(2/3)(3/2)y = 8(3/2)
6x -y = 12
Answer:
Step-by-step explanation:
Answer:
Here is the solution. Hope it helps.
Answer:
y=20
x=4
Step-by-step explanation:
Since you can plug the first 2 coordinates into the slope equation (
) you will get 4 for the slope so for the equation for the parallel line you would get y=4x+4 and since the x=4 you could plug that in and you would get y=20 and x=4
