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3 years ago

Identify square root of 11 as either rational or irrational, and approximate to the tenths place.

Mathematics

2 answers:

Vlada [557]3 years ago

4 0

It's irrational, √11≈3.3

jenyasd209 [6]3 years ago

4 0

The square root of 11 would be irrational. The answer would be approximately 3.3

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4/5 of a number is 32

andrew11 [14]

Answer:

x = 40

Step-by-step explanation:

Step 1: Write out an equation

4/5(x) = 32

Step 2: Solve by dividing both sides by 4/5

x = 32/(4/5)

Use KCF (Keep Change Flip) if you do not have a calc.

x = 40

6 0

3 years ago

Read 2 more answers

ASAP

Katen [24]

Answer:

No , because there are different formulas for each prism.

Step-by-step explanation:

7 0

3 years ago

Write an equation of the line that passes through the given point and is parallel to the given line.

9966 [12]

Answer : Equation of line is y=Equation of line is y= $\frac{2}{3}$ x+ $\frac{-5}{3}$

Step-by-step explanation:

Theory :

Equation of line is given as y = mx + c.

Where, m is slope and c is y intercepted.

Slope of given line : y = $\frac{2}{3}$ x+1 is m= $\frac{2}{3}$

We know that line : y = $\frac{2}{3}$ x+1 is parallel to equation of target line.

therefore, slope of target line will be $\frac{2}{3}$ .

we write equation of target line as y= $\frac{2}{3}$ x+c

Now, It is given that target line passes through point ( -5,-2)

hence, point ( -5,-2) satisfy the target line's equation.

we get,

y= $\frac{2}{3}$ x+c

-2= $\frac{2}{3}$ $\times$ -5+ c

-5= $\frac{-10}{3}$ +c

c= $\frac{-5}{3}$

thus, Equation of line is y=Equation of line is y= $\frac{2}{3}$ x+ $\frac{-5}{3}$

7 0

3 years ago

Can I get help solving this graph please?

Daniel [21]

see the attached figure with the letters

1) find m(x) in the interval A,B
A (0,100) B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100

2) find m(x) in the interval B,C
B(50,40) C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20

3) find n(x) in the interval A,B
A (0,0) B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x

4) find n(x) in the interval B,C
B(50,60) C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30

5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find h'(x)
h'(x)=-36/25=-1.44

6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x)
h'(x)=18/25=0.72

for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72

 h'(x) = 1.44 ------------ > not exist

8 0

3 years ago

What is the square root of x?

sveticcg [70]

Cant answer this without giving an equation

7 0

3 years ago