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Sati [7]
2 years ago
13

There are 10 apples for every 6 bananas how many bananas are there if there are 20 apples?

Mathematics
2 answers:
netineya [11]2 years ago
7 0
If there are 10 apples for every 6 bananas, then there would be 12 bananas if there are 20 apples & 9 bananas if there are 15 apples.
mr Goodwill [35]2 years ago
4 0

Answer:

make a graph thats how you could do it if there are 15 apples there would be 19 apples

i think if im corect can i get brainly....if i am

Step-by-step explanation:

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X^2+9x+20=0<br><br> What are the steps to solve by factoring?
Dimas [21]
First simplify the equation and next multiply the 20 with the x^2 and find a number that adds together to give you the middle
6 0
3 years ago
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Express the illuminance on the floor as a composite function of t for 0 &lt; t &lt; 8.
GrogVix [38]
The formula for illuminance is given by
E = I / d^2
This formula only holds true for one-dimensional illuminance
The problem asks for the illuminance across the floor. We need to use two variables, x and y.
From Pythagorean Theorem
d^2 = x^2 + y^2
and from Trigonometry
x = d cos t
y = d sin t

The function for the illuminance can be represented by the composite function
E = I cos² t / x²
and
E = I sin² t / y²

The boundary of these functions is:
<span>0 < t < 8
So, the value of t must be in radians and not in degrees</span>
3 0
3 years ago
3 7/10 x 7 what is the answer in fraction form or decimal form. Perhaps both
ElenaW [278]

Answer:

Step-by-step explanation:

3 7/10 *7

37/10 *7

259/10

25.9 or 25 9/10

5 0
3 years ago
Consider a uniform distribution from aequals4 to bequals29. ​(a) Find the probability that x lies between 7 and 27. ​(b) Find th
weeeeeb [17]

Answer:

a) 80% probability that x lies between 7 and 27.

b) 28% probability that x lies between 6 and 13.

c) 44% probability that x lies between 9 and 20.

d) 28% probability that x lies between 11 and 18.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value x between c and d, in which d is larger than c, is given by the following formula.

P(c \leq x \leq d) = \frac{d - c}{b - a}

Uniform distribution from a = 4 to b = 29

(a) Find the probability that x lies between 7 and 27.

So c = 7, d = 27

P(7 \leq x \leq 27) = \frac{27 - 7}{29 - 4} = 0.8

80% probability that x lies between 7 and 27.

​(b) Find the probability that x lies between 6 and 13. ​

So c = 6, d = 13

P(6 \leq x \leq 13) = \frac{13 - 6}{29 - 4} = 0.28

28% probability that x lies between 6 and 13.

(c) Find the probability that x lies between 9 and 20.

​So c = 9, d = 20

P(9 \leq x \leq 20) = \frac{20 - 9}{29 - 4} = 0.44

44% probability that x lies between 9 and 20.

(d) Find the probability that x lies between 11 and 18.

So c = 11, d = 18

P(11 \leq x \leq 18) = \frac{18 - 11}{29 - 4} = 0.28

28% probability that x lies between 11 and 18.

3 0
2 years ago
Count back write the difference = 11 - 3
sergey [27]

Answer:

11-3=8

Step-by-step explanation:

so your answer is going to equal 8

4 0
3 years ago
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