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4 years ago

10

Solve the following inequality:1-2-m>3

1 answer:

slava [35]4 years ago

8 0

Answer:

m < -4

Step-by-step explanation:

1-2-m>3

Combine like terms

-1-m > 3

Add 1 to each side

-1+1-m > 3+1

-m> 4

Divide each side by -1, remembering to flip the inequality

-m/-1 < 4/-1

m < -4

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Sliva [168]

Answer:

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Step-by-step explanation:

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3 years ago

Select the best answer for the question 9/11=/22

miss Akunina [59]

9/11=x/22

11*2=22
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x=18

9/11=18/22

4 0

4 years ago

Read 2 more answers

Help me asp 25 points and will mark

denpristay [2]

Y=10x, 10 is the amount of money Miranda earns per hour , x is the amount of hours she works, y is the total amount of money she earns.
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8 0

3 years ago

HELP PRETTY PLEASE THIS IS URGENT NEED IN THE NEXT HOUR!!

zmey [24]

Answer:

(- 2, 6 )

Step-by-step explanation:

Given the equations

3x + 2y = 6 → (1)

$\frac{2}{3}$ y - x = 6 ( multiply through by 3 to clear the fraction )

2y - 3x = 18 ( add 3x to both sides )

2y = 18 + 3x → (2)

Substitute 2y = 18 + 3x into (1)

3x + 18 + 3x = 6

6x + 18 = 6 ( subtract 18 from both sides )

6x = - 12 ( divide both sides by 6 )

x = - 2

Substitute x = - 2 into (1) and solve for y

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7 0

3 years ago

A private and a public university are located in the same city. For the private university, 1038 alumni were surveyed and 647 sa

Snezhnost [94]

Answer:

The difference in the sample proportions is not statistically significant at 0.05 significance level.

Step-by-step explanation:

Significance level is missing, it is α=0.05

Let p(public) be the proportion of alumni of the public university who attended at least one class reunion

p(private) be the proportion of alumni of the private university who attended at least one class reunion

Hypotheses are:

$H_{0}$ : p(public) = p(private)

$H_{a}$ : p(public) ≠ p(private)

The formula for the test statistic is given as:

z= $\frac{p1-p2}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}}$ where

p1 is the sample proportion of public university students who attended at least one class reunion ( $\frac{808}{1311}=0.616$ )

p2 is the sample proportion of private university students who attended at least one class reunion ( $\frac{647}{1038}=0.623$ )

p is the pool proportion of p1 and p2 ( $\frac{808+647}{1311+1038}=0.619$ )

n1 is the sample size of the alumni from public university (1311)

n2 is the sample size of the students from private university (1038)

Then z= $\frac{0.616-0.623}{\sqrt{{0.619*0.381*(\frac{1}{1311} +\frac{1}{1038}) }}}$ =-0.207

Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.

6 0

4 years ago