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nexus9112 [7]
3 years ago
6

If (x) = 3x - 5 and g(x) = x + 3, find (f - g)(x).

Mathematics
2 answers:
Temka [501]3 years ago
8 0

Answer:

2x -8

Step-by-step explanation:

f (x) = 3x - 5

g(x) = x + 3,

(f - g)(x) = 3x - 5 - ( x+3)

Distribute the minus sign

            = 3x-5 -x-3

Combine like terms

           = 2x -8

yarga [219]3 years ago
4 0

Answer:

C

Step-by-step explanation:

(f-g)(x)=(3x-5)-(x+3) = 3x-5-x-3 = 2x-8

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Answer:

B or

Lower quartile: 124

Median: 131

Upper quartile: 137

Step-by-step explanation:

To find the median first make the data in order from greatest to least:

118,122,124,129,129,133,135,137,139,142

Then find the middle 2 numbers which are 129 and 133

129+133=262 (divide by 2 to find average) so

median= 262/2=131

To find the Lower quartile find the number in the middle of the first 5 numbers which is 124

To find the Upper quartile find the number in the middle of the second 5 numbers which is 137 so

B or

Lower quartile: 124

Median: 131

Upper quartile: 137

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3 years ago
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What’s v,j,a with a dilation of 4
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Answer:

Perform a Dilation of 4 on point A (2, 3) which you can see in the picture below. Multiply the coordinates of the original point (2, 3), called the image, by 4. Image's coordinates = (2 * 4, 3 * 4) to get the coordinates of the image (8, 12).

Step-by-step explanation:

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3 years ago
A car has mass 1500 kg and is traveling at a speed of 35 miles/hour. what is its kinetic energy in joules? (Be sure to convert m
photoshop1234 [79]

Answer:

Factor by which kinetic energy increase = 4 times

Step-by-step explanation:

Given,

  • Mass of the car, v1 = 1500 kg
  • initial speed of car = 35 miles/h

                               =\dfrac{35\times 1609.34}{3600}\ m/s

                               = 15.64 m/s

Initial kinetic energy of the car is given by,

k_1\ =\ \dfrac{1}{2}.m.v_1^2

       =\ \dfrac{1}{2}\times 1500\times (15.64)^2\ joule

       = 183606.46 J

  • Final velocity of car v2 = 70 miles/hour

                                      =\dfrac{70\times 1609.34}{3600}

                                      = 31.29 m/s

So, final kinetic energy of car is given by

k_2\ =\ \dfrac{1}{2}.m.v_2^2

        =\ \dfrac{1}{2}\times 1500\times (31.29)^2

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Now, the ratio of final to initial kinetic energy can be given by,

\dfrac{k_2}{k_1}=\ \dfrac{734425.84}{183606.46}

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Hence, the kinetic energy will increase by 4 times.

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