Diane's question is not a statistical question because there <u>is not</u> variability in the response, and because data <u>has</u> to be collected to answer it.
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−<em>Kallmekrish</em>
The probability that the train will be there when Alex arrives is 5/18
If Alex arrives at any time after 1.20pm the chances that train will be there is 1/3.
However if alex arrives at 1.00pm exactly there is no chance the train will be arrive there.
The probability that the train will be there increase linearly to 1/3 as alex's arrival time moves from 1.00pm to 1.20pm.
By arranging the probabilities over the first 20 minutes to get a 1/6 chance the train will be there if alex arrives between 1.00pm to 1.20pm
we get the final answer by
=1/3( 1/6 + 1/3 + 1/3)
=5/18
So, the probability that the train will be there when Alex arrives is 5/18
Learn more about PROBABILITY here
brainly.com/question/24756209
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Answer:
201
Step-by-step explanation:
I'm smart ok trust me ON this one if I'M wrong at least I tried
Step-by-step explanation:
We need to find an expression for
.
We can solve it as follows.
We know that,

So,

or

Hence, this is the required solution.
Answer:
Step-by-step explanation:
Let the number be x,
2x+4 = 3x-7
Collect like terms
2x-3x= -4-7
-x =. -11
Multiply both sides by -1
x. =. 11
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