Answer:
21
Step-by-step explanation:
Answer: a package of cookies cost $ 5 and each bag of chips cost $5
Step-by-step explanation:
Let x represent the cost of a package of cookies and y represent the cost of a bap of chips ,then from the first statement :
4x + 4y = 40
dividing through by 4 , we have
x + y = 10 ........................... equation 1
From the second statement
3x + 5y = 40 ..................... equation 2
Solving the system of linear equation by substitution method , from equation 1 , make x the subject of the formula , that is
x = 10 - y ................... equation 3
substitute x = 10 - y into equation 2 , we have :
3 (10 - y ) + 5y = 40
30 - 3y + 5y = 40
30 + 2y = 40
subtract 30 from both sides
2y = 40 -30
2y = 10
y = 5
substitute y = 5 into equation 3 , equation 3 becomes
x = 10 - 5
x = 5
Therefore ; a package of cookies cost $ 5 and each bag of chips cost $5
Given:
• Amount to save, A = $28,000
,
• Time, t = 6 years
,
• Interest rate, r = 5.3% ==> 0.053
,
• Number of times compounded = quarterly = 4 times
Let's find the amount that must be deposited into the account quarterly.
Apply the formula:

Where:
FV is the future value = $28,000
r = 0.053
n = 4
t = 6 years
Thus, we have:

Let's solve for P.
We have:

Solving further:

Divide both sides by 28.0384237:

Therefore, the amount that must be deposited quarterly into the account is $998.60
ANSWER:
$998.60
A = amount invested at 4%.
b = amount invested at 9%.
we know the total amount invested was $26500, thus
a + b = 26500.
whatever% of anything is just (whatever/100) * anything.
how much is 4% of a? well, is just (4/100) * a, or
0.04a.
how much is 9% of b? well, is just (9/100) * b, or
0.09b.
we know the interest yielded for both amounts adds up to $1510, thus
0.04a + 0.09b = 1510.

how much was invested at 9%? well, b = 26500 - a.
X² -x -6 = (x -3)(x +2)
The factors are ...
x - 3
x + 2