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kobusy [5.1K]
3 years ago
8

Lynn works as a part-time vendor selling necklaces for $15 each and bangles for $10 each. She needs to earn a minimum of $300 pe

r week to cover her expenses. The inequality that represents this situation is graphed here. Which statement is true? A. Lynn will meet her goal if she sells 12 bangles and 12 necklaces. B. Lynn will meet her goal if she sells 20 bangles and 6 necklaces. C. Lynn will meet her goal if she sells 6 bangles and 12 necklaces. D. Lynn will meet her goal if she sells 2 bangles and 18 necklaces.

Mathematics
2 answers:
timofeeve [1]3 years ago
7 0

A,B,C,D i.e. all statements are true!

<u>Step-by-step explanation:</u>

According to question, Lynn works as a part-time vendor selling necklaces for $15 each and bangles for $10 each. She needs to earn a minimum of $300 per week to cover her expenses. The inequality for above scenario will be :

15x + 10y\geq 300 where, x is number of necklaces & y is number of bangles.

A.

Lynn will meet her goal if she sells 12 bangles and 12 necklaces. i.e. x=12 and y=12 , putting values inequality : 15(12) + 10(12)  = 300 which follows inequality . True statement!

B.

Lynn will meet her goal if she sells 20 bangles and 6 necklaces.

putting values inequality : 15(6) + 10(20) = 290 which follows inequality . True statement!

C.

Lynn will meet her goal if she sells 6 bangles and 12 necklaces. putting values inequality : 15(12) + 10(6) = 240, which follows inequality . True statement!

D.

Lynn will meet her goal if she sells 2 bangles and 18 necklaces.putting values inequality : 15(18) + 10(2)=290, which follows inequality . True statement!

Kaylis [27]3 years ago
4 0

The answer is A.) Lynn will meet her goal if she sells 12 bangles and 12 necklaces.

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