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frosja888 [35]
3 years ago
9

(03.01 MC)

Mathematics
1 answer:
vekshin13 years ago
6 0

Answer:

Option (1) will be the answer.

Step-by-step explanation:

Coordinates of the points A and B lying on the line f are (0, 2) and (2, 0) respectively.

Slope of the line f,

m_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m_{1}=\frac{2-0}{0-2}

m_{1}=-1

After dilation of line f by a scale factor of 2, coordinates of A' and B' will be,

Rule for dilation,

(x, y) → (kx, ky)

Where k = scale factor

A(0, 2) → A'(0, 4)

B(2, 0) → B'(4, 0)

Slope of line f',

m_{2}=\frac{0-4}{4-0}

m_{2}=-1

Since, m_{1}=m_{2}=-1

Therefore, both the lines f and f' will be parallel.

Option (1) will be the answer.

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5 0
3 years ago
manuel deposits $10000 for 12 yr in an account paying 4% compounded annually.He then puts this total amount on deposit in anothe
Naddik [55]
\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$10000\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
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\end{array}\to &1\\
t=years\to &12
\end{cases}
\\\\\\
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he then turns around and grabs that money and sticks it for another 9 years,

\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
~~
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$16010.32\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2\\
t=years\to &9
\end{cases}
\\\\\\
A=16010.32\left(1+\frac{0.05}{2}\right)^{2\cdot 9}\implies A=16010.32(1.025)^{18}
\\\\\\
A\approx 24970.64

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