A rectangular athletic field is twice as long as it is wide. if the perimeter of the athletic field is 192 yards, what are its
dimensions
1 answer:
P = 2(L + W)
P = 192
L = 2W
192 = 2(2W + W)
192 = 2(3W)
192 = 6W
192/6 = W
32 = W <=== the width is 32 yards
L = 2W
L = 2(32)
L = 64 <=== the length is 64 yards
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