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oksian1 [2.3K]
3 years ago
9

A rectangular athletic field is twice as long as it is wide. if the perimeter of the athletic field is 192 ​yards, what are its​

dimensions
Mathematics
1 answer:
qaws [65]3 years ago
5 0
P = 2(L + W)
P = 192
L = 2W

192 = 2(2W + W)
192 = 2(3W)
192 = 6W
192/6 = W
32 = W <=== the width is 32 yards

L = 2W
L = 2(32)
L = 64 <=== the length is 64 yards
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(I went too far in my explanation; I'm not going to erase it because I think it is important to have an example on solving these)

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