1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
stepan [7]
3 years ago
5

R(-5, 5) S(1, 7) T(2, 4) U(-4, 2)

Mathematics
1 answer:
natali 33 [55]3 years ago
4 0
Would you like to solve this problem or give you the description of it
You might be interested in
Write an equation in slope-intercept form? (12,5); y=2/3x-1
Marina86 [1]

Answer:

y-5=2/3x(12-x) would be point form

3 0
3 years ago
Sarah's heart beats 2,760 times during 20
GrogVix [38]

Answer:

When Sarah is resting her heart rate is much lower.

Hope that helps :)
4 0
3 years ago
You add 10g of lemonade powder to 50g of water. How much lemonade do you have to drink?
Grace [21]

Answer:

You have to drink 60g of lemonade.

Step-by-step explanation:

When you combine two things and one of them dissolves in the other then the entire amount becomes one thing, and by the conservation of mass the amount of total lemonade is 60g.

4 0
3 years ago
Read 2 more answers
Let C(x) be the statement "x has a cat," let D(x) be the statement "x has a dog," and let F(x) be the statement "x has a ferret.
jek_recluse [69]

Answer:

\mathbf{a)} \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)\\\mathbf{b)} \left( \forall x \in X\right) \; C(x) \; \vee \; D(x) \; \vee \; F(x)\\\mathbf{c)} \left( \exists x \in X\right) \; C(x) \; \wedge \; F(x) \; \wedge \left(\neg \; D(x) \right)\\\mathbf{d)} \left( \forall x \in X\right) \; \neg C(x) \; \vee \; \neg D(x) \; \vee \; \neg F(x)\\\mathbf{e)} \left((\exists x\in X)C(x) \right) \wedge  \left((\exists x\in X) D(x) \right) \wedge \left((\exists x\in X) F(x) \right)

Step-by-step explanation:

Let X be a set of all students in your class. The set X is the domain. Denote

                                        C(x) -  ' \text{$x $ has a cat}'\\D(x) -  ' \text{$x$ has a dog}'\\F(x) -  ' \text{$x$ has a ferret}'

\mathbf{a)}

Consider the statement '<em>A student in your class has a cat, a dog, and a ferret</em>'. This means that \exists x \in X so that all three statements C(x), D(x) and F(x) are true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

                         \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)

\mathbf{b)}

Consider the statement '<em>All students in your class have a cat, a dog, or a ferret.' </em>This means that \forall x \in X at least one of the statements C(x), D(x) and F(x) is true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

                        \left( \forall x \in X\right) \; C(x) \; \vee \; D(x) \; \vee F(x)

\mathbf{c)}

Consider the statement '<em>Some student in your class has a cat and a ferret, but not a dog.' </em>This means that \exists x \in X so that the statements C(x), F(x) are true and the negation of the statement D(x) . We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

                      \left( \exists x \in X\right) \; C(x) \; \wedge \; F(x) \; \wedge \left(\neg \; D(x) \right)

\mathbf{d)}

Consider the statement '<em>No student in your class has a cat, a dog, and a ferret..' </em>This means that \forall x \in X none of  the statements C(x), D(x) and F(x) are true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as a negation of the statement in the part a), as follows

\neg \left( \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)\right) \iff \left( \forall x \in X\right) \; \neg C(x) \; \vee \; \neg D(x) \; \vee \; \neg F(x)

\mathbf{e)}

Consider the statement '<em> For each of the three animals, cats, dogs, and ferrets, there is a student in your class who has this animal as a pet.' </em>

This means that for each of the statements C, F and D there is an element from the domain X so that each statement holds true.

We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

           \left((\exists x\in X)C(x) \right) \wedge  \left((\exists x\in X) D(x) \right) \wedge \left((\exists x\in X) F(x) \right)

5 0
3 years ago
The first is 4 inches wide and 15 inches long. ​The second is 9 inches wide. ​ ​Find the length of the second rectangle. A 6.67
Ray Of Light [21]

Answer:

D - 33.75

Step-by-step explanation:

If the rectangles are similar, then you can use this cheat:

Width:

9/4 = 2.25

2.25 is the scale factor between the two rectangles.

Using the new-found scale factor, you can do this:

15 x 2.25 = 33.75

This means the length on the second rectangle is 33.75 inches long.

Hoping this helps you! :)

3 0
2 years ago
Other questions:
  • What are the factors of the expression 3x(y + 5)?
    13·1 answer
  • How do I solve (4x+1)(x-5)=-43x-41
    12·1 answer
  • 3/4 - 1/3 plz explain
    6·2 answers
  • How to solve 37=-3+5(x+6)
    8·1 answer
  • Can someone help me with this ???
    15·1 answer
  • A cylinder has a circular base with a diameter of 12 ft the height of the cylinder is 4 feet what is the volume of the cylinder
    5·1 answer
  • How many 4-letter “words” can be made using all the letters in BEEP, if the two Es are indistinguishable? Two such “words” to in
    9·1 answer
  • True or false is .00007 times 10 negative 5 irrational number
    8·2 answers
  • 1/3(x - 10) = - 4<br><br> x = ?
    11·2 answers
  • Does anyone know #13????
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!