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4 years ago

Explain, using three examples, why it is important for engineers to do research before beginning a project.

Engineering

1 answer:

Firlakuza [10]4 years ago

4 0

Answer:

It improves problem solving abilities and conceptualization
Creates a competitive edge or approach to research problems
It is vital for quality assurance and testing

Explanation:

When designing a solution to a problem, an engineer performs a research first in the area of problem. This will include understanding other works done by various individuals on similar topics. This shades light to the engineer on the concept of study and challenges him or her to think critically and develop a better solution concerning a problem. When the problem solving abilities are challenged, an engineer could come up with a better solution to a problem in terms of the technology applied and innovations to adjust to as a company thus putting the firm, products, customers and the entire economy at a better place than before in terms of problem solving approaches and solutions. Furthermore, research will offer a chance for quality control which is vital for success of a business in the production of products which meets or surpass users expectations.

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Write a matrix, that is a lower triangular matrix.

shepuryov [24]

Answer:

$\left[\begin{array}{ccc}10&0&0\\14&25&0\\57&18&39\end{array}\right]$

Explanation:

A lower triangular matrix is one whose elements above the main diagonal are zero meanwhile all the main diagonals elements and below are nonzero elements. This is one of the two existing types of triangular matrixes. Attached you will find a image referring more about triangular matrixes.

If there is any question, just let me know.

6 0

4 years ago

The pump of a water distribution system is powered by a 6-kW electric motor whose efficiency is 95 percent. The water flow rate

Sonja [21]

Answer:

a) Mechanical efficiency ( $\varepsilon$ )=63.15% b) Temperature rise= 0.028ºC

Explanation:

For the item a) you have to define the mechanical power introduced (Wmec) to the system and the power transferred to the water (Pw).

The power input (electric motor) is equal to the motor power multiplied by the efficiency. Thus, $Wmec=0.95*6kW=5.7 kW$ .

Then, the power transferred (Pw) to the fluid is equal to the flow rate (Q) multiplied by the pressure jump $\Delta P$ . So $P_W = Q*\Delta P=0.018m^3/s * 200x10^3 Pa=3600W$ .

The efficiency is defined as the ratio between the output energy and the input energy. Then, the mechanical efficiency is $\varepsilon=3.6kW/5.7kW=0.6315=63.15\%$

For the b) item you have to consider that the inefficiency goes to the fluid as heat. So it is necessary to use the equation of the heat capacity but in a "flux" way. Calling <em>H</em> to the heat transfered to the fluid, the specif heat of the water and $\rho$ the density of the water:

$[tex]H=(5.7-3.6) kW=\rho*Q*c*\Delta T=1000kg/m^3*0.018m^3/s*4186J/(kg \ºC)*\Delta T$ [/tex]

Finally, the temperature rise is:

$\Delta T=2100/75348 \ºC=0.028 \ºC$

7 0

3 years ago

Q1) Determine the force in each member of the

Sever21 [200]

Answer:

CD = DE = DF = 0
BC = CE = 15 N tension
FA = 15 N compression
CF = 15√2 N compression
BF = 25 N tension
BG = 55/2 N tension
AB = (25√5)/2 N compression

Explanation:

The only vertical force that can be applied at joint D is that of link CD. Since joint D is stationary, there must be no vertical force. Hence the force in link CD must be zero, as must the force in link DE.

At joint E, the only horizontal force is that applied by link EF, so it, too, must be zero.

Then link CE has 15 N tension.

The downward force in CE must be balanced by an upward force in CF. Of that force, only 1/√2 of it will be vertical, so the force in CF is a compression of 15√2 N.

In order for the horizontal forces at C to be balanced the 15 N horizontal compression in CF must be balanced by a 15 N tension in BC.

At joint F, the 15 N horizontal compression in CF must be balanced by a 15 N compression in FA. CF contributes a downward force of 15 N at joint F. Together with the external load of 10 N, the total downward force at F is 25 N. Then the tension in BF must be 25 N to balance that.

At joint B, the 25 N downward vertical force in BF must be balanced by the vertical component of the compressive force in AB. That component is 2/√5 of the total force in AB, which must be a compression of 25√5/2 N.

The <em>horizontal</em> forces at joint B include the 15 N tension in BC and the 25/2 N compression in AB. These are balanced by a (25/2+15) N = 55/2 N tension in BG.

In summary, the link forces are ...

(25√5)/2 N compression in AB
15 N tension in BC
25 N tension in BF
0 N in CD, DE, and EF
15 N tension in CE
15√2 compression in CF
15 N compression in FA

_____

Note that the forces at the pins of G and A are in accordance with those that give a net torque about those point of 0, serving as a check on the above calculations.

8 0

3 years ago

I need help with my autos

oksano4ka [1.4K]

Answer:

what is wrong with it and what is the question

Explanation:

6 0

3 years ago

The author claims that engineers should always have the final say and last word when it comes to setting safety standards. Selec

Lisa [10]

Answer:

I select false because engineers are not the only thing we have, we have scientists doctors mathematicians and much more to give safety standards

4 0

4 years ago

Read 2 more answers