Answer:
Step One: Know What Your Rocket Needs to Do. ...
Step Two: Establish Mission Parameters. ...
Step Three: Call in Experts. ...
Step Four: Start Drawing. ...
Step Five: Whittle Down the Possibilities. ...
Step Six: Pick the Best Design.
Explanation:
Hope this helps and thx for tha fwee pts
Answer:
the pressure reading when connected a pressure gauge is 543.44 kPa
Explanation:
Given data
tank volume (V) = 400 L i.e 0.4 m³
temperature (T) = 25°C i.e. 25°C + 273 = 298 K
air mass (m) = 3 kg
atmospheric pressure = 98 kPa
To find out
pressure reading
Solution
we have find out pressure reading by gauge pressure
i.e. gauge pressure = absolute pressure - atmospheric pressure
first we find absolute pressure (p) by the ideal gas condition
i.e pV = mRT
p = mRT / V
p = ( 3 × 0.287 × 298 ) / 0.4
p = 641.44 kPa
so
gauge pressure = absolute pressure - atmospheric pressure
gauge pressure = 641.44 - 98
gauge pressure = 543.44 kPa
365gpa I don’t even know what it is but this is with 10 point and I need it
Answer:
import java.util.*;
public class PerfectNum{
public static String isPerfect(long number){
String s = "";
long sum = 0;
//Checking if the number is perfect or not
for(long i = 1; i < number; i++){
if(number % i == 0){
sum += i;
}
}
if(sum == number){
for(long i = 1; i < number; i++){
String t = "";
if(number % i == 0){
long n = i;
//Converting into string
while(n > 0){
long p = n % 10;
t += (char)(p + '0');
n /= 10;
}
//Reversing the number
for(int j = t.length() - 1; j >= 0; j--){
s += t.charAt(j);
}
s += " ";
}
}
}
return s;
}
public static void main(String[] args){
Scanner sc = new Scanner(System.in);
System.out.println("Enter maximum number");
long n = sc.nextLong();
System.out.println("Displaying perfect numbers 2 to " + n);
for(long i = 2; i <= n; i++){
String s = isPerfect(i);
if(s != "")
System.out.println(s +"->" + i);
}
}
}