given that ∆ABC is congruent to ∆DBC, AB = 10, and Angle A = 44°. Angle D must be 44° as well since you can tell that angle abc is 88° and is not a right angle, and due to the corresponding parts. You can also think about these triangle as angles since angle abc = angle dbc. The other angles can be calculated using the triangle sum theorem since both triangles share side bc so angle acb and dcb are right angles(90°)
therefore 180-(44+90) = 46° which the measure of angles abc and dcb.
This measure would only make it true because of triangle congruency.
