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AURORKA [14]
2 years ago
15

Help!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
stealth61 [152]2 years ago
7 0
I need more info to help you on this
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You deposit money into an
nadya68 [22]

The amount of money you deposit into the account is $3000

<h3>How much money did you deposit into the account? </h3>

The given parameters are

Rate, r = 8%

Time, t = 5 years

Interest, I = $1200

The formula of simple interest is

I = PRT

So, we have

1200 = I * 8% * 5

This gives

1200 = I * 0.4

Divide both sides by 0.4

I = 3000

Hence, the amount of money you deposit into the account is $3000

Read more about simple interest at:

brainly.com/question/20690803

#SPJ1

7 0
1 year ago
Hi. I need help with these<br> See image for question<br> Answer no 8 ,9 and 10
Nezavi [6.7K]

Answer:

  • 8) 4 + 2q²/p² - 4r/p + r²/p²
  • 9) (3/4, -9/4)
  • 10) (3/8, 41/16)

Step-by-step explanation:

8. ============

Given

  • α and β are roots of px² + qx + r = 0

The sum of the roots is α + β = -q/p, the product of then roots αβ = r/p

  • (2 + α²)(2 + β²) =  
  • 4 + 2(α² + β²) + (αβ)² =
  • 4 + 2((α + β)² -2αβ) + (αβ)² =
  • 4 + 2((-q/p)² - 2r/p) + (r/p)² =
  • 4 + 2q²/p² - 4r/p + r²/p²

------------------------------

9. ============

<u>Given function</u>

  • y = 2x² - 3x - 1

The minimum point is reached at vertex

<u>The vertex is:</u>

  • x = -b/2a
  • x = -(-3)/2*2 = 3/4

<u>The corresponding y-coordinate is:</u>

  • y = 2(3/4)² - 3(3/4) - 1 = 9/8 - 9/4 - 1 = 1/8(9 - 18 - 9) = - 18/8 = - 9/4

<u>So the point is: </u>

  • (3/4, -9/4)

---------------

10. ============

<u>Given function</u>

  • y = 2 - 3x - 4x²

The maximum is reached at vertex

<u>The vertex is:</u>

  • x = -b/2a
  • x = -(-3)/2(-4) = -3/8

<u>The corresponding y-coordinate is:</u>

  • y = 2 - 3(-3/8) -4(-3/8)² = 2 + 9/8 - 9/16 = 1/16(32 + 18 - 9) = 41/16

<u>So the maximum point is:</u>

  • (3/8, 41/16)

4 0
2 years ago
PLEASE HELP!
Luba_88 [7]
2x - 2y = 2

2x - 2 x 0 = 2

2x - 0 = 2

2x = 2

x = 1

2x - 2y = 2

2 x 0 - 2y = 2

y = - 1
3 0
3 years ago
Read 2 more answers
Prove that: (a2 - b2)3 + (b2-c2)3+ (c2-a2)3 = 3 (a+b) (b+c) (c+a) (a-b) (b-c) (c-a).
Vanyuwa [196]
L=(a^2-b^2)^3+(b^2-c^2)^3+(c^2-a^2)^3=(*)\\\\(a^2-b^2)^3=a^6-3a^4b^2+3a^2b^4-b^6\\\\(b^2-c^2)^3=b^6-3b^4c^2+3b^3c^4-c^6\\\\(c^2-a^2)^3=c^6-3c^4a^2+3c^2a^4-a^6\\\\(*)=a^6-3a^4b^2+3a^2b^4-b^6+b^6-3b^4c^2+3b^2c^4-c^6+c^6-\dots\\\dots-3c^4a^2+3c^2a^4-a^6\\\\=-3a^4b^2+3a^2b^4-3b^4c^2+3b^2c^4-3c^4a^2+3c^2a^4\\\\=3(-a^4b^2+a^2b^4-b^4c^2+b^2c^4-a^2c^4+a^4c^2)

R=3(a+b)(a-b)(b+c)(b-c)(c+a)(c-a)\\\\=3(a^2-b^2)(b^2-c^2)(c^2-a^2)\\\\=3(a^2b^2-a^2c^2-b^4+b^2c^2)(c^2-a^2)\\\\=3(a^2b^2c^2-a^4b^2-a^2c^4+a^4c^2-b^4c^2+a^2b^4+b^2c^4-a^2b^2c^2)\\\\=3(-a^4b^2+a^2b^4-b^4c^2+b^2c^4-a^2c^4+a^4c^2)\\\\L=R
5 0
3 years ago
Read 2 more answers
Identify all number sets to which the square root of 25 belongs to.
const2013 [10]

Answer:

SOLUTION: Explain why the square root of 25 belongs to 4 subsets of the real numbers , but the square root of 5 only belongs to 1 . tell which subsets each belong to and why .

Step-by-step explanation:

The square root of 25 is 5, which  

1. A rational number, since 5 is the ratio of the two integers 5 and 1.

2. An integer since 5 is an element of {...,-3,-2,-1,0,1,2,3,.}  

3. A whole number, since 5 is an element of {0,1,2,3.}

4. A counting number, since 5 is an element of {1,2,3,}

The square root of 5 is only  

1. An irrational number, since it is not the ratio of any two integers.

[It can only be approximated by

this nonrepeating infinite decimal, it goes on forever:

2.2360679774997896964091736687312762354406183596115257...]

4 0
2 years ago
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