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Readme [11.4K]
3 years ago
12

Name the value of given digits in the number below the 9s in 299

Mathematics
1 answer:
Igoryamba3 years ago
5 0

Ones And Tens.

I hope this helped.

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How many soutions does this equation have?
DiKsa [7]

Answer:

\huge\colorbox{pink}{✏﹏ \: C. \: Infinite Solutions \: }

➳ These equations will have <u>infinite solutions</u> because they are in 2 variables. Any value can be substituted in the place of the variables x & y.

8 0
2 years ago
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What is the difference between finding the greatest common factor and the least common multiple of the numbers 4 and 12?
dangina [55]

Answer: The difference is factor is a circumstance, fact, or influence that contributes to a result or outcome. and multiple is A multiple of a number is that number multiplied by an integer.


Step-by-step explanation:


8 0
3 years ago
it looks as though you made 72 of your goal so far for the month you only have 5 days left to reach 100% of your goal let me rem
dezoksy [38]
72% can also be written as 0.72, so take 0.72 x 45 = 32.4     

Subtract 32.4 from 45    45 - 32.4 = 12.6    You need 12.6 renewals in 5 days.
8 0
3 years ago
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Find the distance between points P(5, 1) and Q(3, 4) to the nearest tenth
pav-90 [236]

Answer:

\sqrt{13} units

Step-by-step explanation:

The distance formula is d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} where d is the distance between points (x_1,y_1) and (x_2,y_2). Let (x_1,y_1)\rightarrow(5,1) and (x_2,y_2)\rightarrow(3,4), thus:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\d=\sqrt{(3-5)^2+(4-1)^2}\\\\d=\sqrt{(-2)^2+(3)^2}\\\\d=\sqrt{4+9}\\\\d=\sqrt{13}

Therefore, the distance between points P(5,1) and Q(3,4) is \sqrt{13} units.

8 0
2 years ago
What is the focus of the parabola? <img src="https://tex.z-dn.net/?f=y%3D%20%5Cfrac%7B1%7D%7B4%7D%20x%5E%7B2%7D%20-x%2B3" id="Te
OlgaM077 [116]
We know that
the equation of the parabola is of the form
y=ax²+bx+c
in this problem
y=1/4x²−x+3
where
a=1/4
b=-1
c=3
 the coordinates of the focus are
(-b/2a,(1-D)/4a)
where D is the discriminant b²-4ac
D=(-1)²-4*(1/4)*3-----> D=1-3---> D=-2
therefore
x coordinate of the focus
-b/2a----> 1/[2*(-1/4)]----> 2

y coordinate of the focus
(1-D)/4a------> (1+2)/(4/4)---> 3

the coordinates of the focus are (2,3)
3 0
2 years ago
Read 2 more answers
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