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son4ous [18]
2 years ago
6

8. Find (f+g)(x) if f(x) = 4x² - 5x and g(x) = 3x² + 6x - 4.​

Mathematics
1 answer:
lilavasa [31]2 years ago
5 0

{\qquad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

\qquad \sf  \dashrightarrow \: (f + g)(x)

\qquad \sf  \dashrightarrow \: f(x) + g(x)

\qquad \sf  \dashrightarrow \: (4 {x}^{2}  - 5x) + (3 {x}^{2}  + 6x - 4)

\qquad \sf  \dashrightarrow \: 7 {x}^{2}  + x - 4

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<img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B5x%2F8y%7D" id="TexFormula1" title="\sqrt[4]{5x/8y}" alt="\sqrt[4]{5x/8y}" al
Furkat [3]

Answer:  \frac{\sqrt[4]{10xy^3}}{2y}

where y is positive.

The 2y in the denominator is not inside the fourth root

==================================================

Work Shown:

\sqrt[4]{\frac{5x}{8y}}\\\\\\\sqrt[4]{\frac{5x*2y^3}{8y*2y^3}}\ \ \text{.... multiply top and bottom by } 2y^3\\\\\\\sqrt[4]{\frac{10xy^3}{16y^4}}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{16y^4}} \ \ \text{ ... break up the fourth root}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{(2y)^4}} \ \ \text{ ... rewrite } 16y^4 \text{ as } (2y)^4\\\\\\\frac{\sqrt[4]{10xy^3}}{2y} \ \ \text{... where y is positive}\\\\\\

The idea is to get something of the form a^4 in the denominator. In this case, a = 2y

To be able to reach the 16y^4, your teacher gave the hint to multiply top and bottom by 2y^3

For more examples, search out "rationalizing the denominator".

Keep in mind that \sqrt[4]{(2y)^4} = 2y only works if y isn't negative.

If y could be negative, then we'd have to say \sqrt[4]{(2y)^4} = |2y|. The absolute value bars ensure the result is never negative.

Furthermore, to avoid dividing by zero, we can't have y = 0. So all of this works as long as y > 0.

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2 years ago
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3 years ago
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Which second degree polynomial function has a leading coefficient of –1 and root 4 with multiplicity 2?
Fynjy0 [20]

Answer:

-(x-4)^{2}

or -x^{2}+8x-16

Step-by-step explanation:

Given a second degree polynomial has a root 4 with multiplicity 2

That means, 4 is a repeating root of the polynomial.

Any second degree polynomial has at most 2 real roots.

⇒Both roots of the polynomial are 4.

and its expression can be written as c·(x-4)^{2} where c is a real number

⇒c·(x^{2}-8x+16)

⇒cx^{2}-8cx+16c

Also, the leading coefficient is given as -1

So, c = -1

and the expression becomes (-1)x^{2}-8·(-1)·x+16·(-1)

⇒<u>-x^{2}+8x-16</u>

7 0
3 years ago
Which expression is the factored form of −1.5w+7.5 ?
tresset_1 [31]
The correct answer is C) -1.5(w-5).

Both numbers are divisible by 1.5.  Since there is a negative in the first term, we will factor that out as well.  This means we are dividing both terms by -1.5:

-1.5(     )

Taking -1.5 out of -1.5w, we have w left:

-1.5(w    )

Dividing 7.5 by -1.5, we have -5:

-1.5(w-5)
5 0
3 years ago
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