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3 years ago

If a superball is bounced from a height of 20 feet, the function

Mathematics

1 answer:

Alex3 years ago

7 0

This question is not complete because the function given was not correctly written.

Complete question:

If a Super ball is bounced from a height of 20 feet, the function F(x) = 20(0.9)ˣ gives the height of the ball in feet of each bounce, where x is the bounce number. What will be the height of the 6th bounce? Round your answer to the nearest tenth of a foot.

Answer:

The height of the ball after the sixth bounce to the nearest tenth of a foot = 10.6 feet

Step-by-step explanation:

Function representing the height of a ball in the question

F(x) = 20(0.9)ˣ

x= number of times which the ball has been bounced In the question, we are given x as 6 times

The height after the 6th bounce is calculated as =

F(x)= 20(0.9)ˣ

F(x) = 20(0.9)⁶

F(6) = 20 × 0.531441

F(6) = 10.62882 feet

Approximately to the nearest tenth = 10.6 feet.

Therefore, the height of the ball after the 6th bounce in feet to the nearest tenth is 10.6 feet.

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System of equation by using substitution <br> 3=y+3x<br> -x+3y=29

Marianna [84]

Answer:

x=-2

y=9

Step-by-step explanation:

3=y+3x ---- A

-x+3y=29 ----B

step 1. rearrange equation A, so you have the "y" variable on one side

3=y+3x

-3x -3x

3-3x=y

y=3-3x ---- C

step 2. Substitute equation C into equation B in place of "y"

-x+3(3-3x)=29 ---foil

-x+9-9x=29 -- collect like terms

-10x+9=29

-9 -9

-10x=20

÷-10 ÷-10

x=-2

Step 3. Substitute x=-2 into equation C to find y

y=3-3(-2)

y=3+6

y=9

Check you answer by subsituting x=-2 and y=9 back into equation A and B

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2 years ago

What is 5 3/5 - 4 1/10

Mariulka [41]

Answer:

3/2

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Zach has 3/4 hour to play video games. It takes him 1/12 hours to set up the system. Each round of his favorite game takes 1/6 h

tiny-mole [99]

1/12 + 1/6x = 3/4...multiply everything by common denominator of 12
1 + 2x = 9
2x = 9 - 1
2x = 8
x = 8/2
x = 4 <== he can play 4 rounds

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3 years ago

Read 2 more answers

A box with a square base and open top must have a volume of 296352 c m 3 . We wish to find the dimensions of the box that minimi

mestny [16]

Answer:

Base Length of 84cm
Height of 42 cm.

Step-by-step explanation:

Given a box with a square base and an open top which must have a volume of 296352 cubic centimetre. We want to minimize the amount of material used.

Step 1:

Let the side length of the base =x

Let the height of the box =h

Since the box has a square base

Volume, $V=x^2h=296352$

$h=\dfrac{296352}{x^2}$

Surface Area of the box = Base Area + Area of 4 sides

$A(x,h)=x^2+4xh\\$Substitute h=\dfrac{296352}{x^2}\\A(x)=x^2+4x\left(\dfrac{296352}{x^2}\right)\\A(x)=\dfrac{x^3+1185408}{x}$

Step 2: Find the derivative of A(x)

$If\:A(x)=\dfrac{x^3+1185408}{x}\\A'(x)=\dfrac{2x^3-1185408}{x^2}$

Step 3: Set A'(x)=0 and solve for x

$A'(x)=\dfrac{2x^3-1185408}{x^2}=0\\2x^3-1185408=0\\2x^3=1185408\\$Divide both sides by 2\\x^3=592704\\$Take the cube root of both sides\\x=\sqrt[3]{592704}\\x=84$