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o-na [289]
3 years ago
10

If a superball is bounced from a height of 20 feet, the function

Mathematics
1 answer:
Alex3 years ago
7 0

This question is not complete because the function given was not correctly written.

Complete question:

If a Super ball is bounced from a height of 20 feet, the function F(x) = 20(0.9)ˣ gives the height of the ball in feet of each bounce, where x is the bounce number. What will be the height of the 6th bounce? Round your answer to the nearest tenth of a foot.

Answer:

The height of the ball after the sixth bounce to the nearest tenth of a foot = 10.6 feet  

Step-by-step explanation:

Function representing the height of a ball in the question

F(x) = 20(0.9)ˣ

x= number of times which the ball has been bounced  In the question, we are given x as 6 times

The height after the 6th bounce is calculated as =  

F(x)= 20(0.9)ˣ

F(x) = 20(0.9)⁶

F(6) = 20 × 0.531441

F(6) = 10.62882 feet

Approximately to the nearest tenth = 10.6 feet.  

Therefore, the height of the ball after the 6th bounce in feet to the nearest tenth is 10.6 feet.

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How many elements does A contains if it has 64 subsets​
Amanda [17]
<h3>Answer:  6</h3>

===========================================================

Explanation:

Rule: If a set has n elements in it, then it will have 2^n subsets.

For example, there are n = 3 elements in the set {a,b,c}. This means there are 2^n = 2^3 = 8 subsets. The eight subsets are listed below.

  1. {a,b,c} .... any set is a subset of itself
  2. {a,b}
  3. {a,c}
  4. {b,c}
  5. {a}
  6. {b}
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Subsets 2 through 4 are subsets with exactly 2 elements.  Subsets 5 through 7 are singletons (aka sets with 1 element). The last subset is the empty set which is a subset of any set. You could use the special symbol \varnothing to indicate the empty set.

For more information, check out concepts relating to the power set.

-------------------

The problem is asking what value of n will make 2^n = 64 true.

You could guess-and-check your way to see that 2^n = 64 has the solution n = 6.

Another approach is to follow these steps.

2^n = 64\\\\2^n = 2^6\\\\n = 6

Which is fairly trivial.

Or you can use logarithms to solve for the exponent.

2^n = 64\\\\\text{Log}\left(2^n\right)=\text{Log}\left(64\right)\\\\n*\text{Log}\left(2\right)=\text{Log}\left(64\right)\\\\n=\frac{\text{Log}\left(64\right)}{\text{Log}\left(2\right)}\\\\n\approx\frac{1.80617997398389} {0.30102999566399} \ \text{ ... using base 10 logs}\\\\n\approx5.99999999999983\\\\

Due to rounding error, we don't land exactly on 6 even though we should.

5 0
2 years ago
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Answer:

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Step-by-step explanation:

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The number of child tickets sold that day was 91.

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3 years ago
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