Answer:
Step-by-step explanation:
p=sec0+tan0
=1/cos0 + sin0/cos0
=(1+sin0)/cos0
square both sides
(1+sin)^2 /cos^2 = p^2
(1+sin)^2/(1 - sin^2 ) = p^2
(1+sin)^2/((1-sin)(1+sin)) = p^2
(1+sin)/(1-sin)=p^2
1+sin=p^2-p^sin
sin+p^2sin=p^2-1
sin(1+p^2)=(p^2-1)
sin=(1-p^2)/(1+p^2)
cosec=1/sin
=(1+p^2)/(1-p^2)
Mohamed decided to track the number of leaves on the tree in his backyard each year. the first year, there were 500 leaves. each year thereafter, the number of leaves was 40% more than the year before. let f(n) be the number of leaves on the tree in Mohamed's backyard in the n^th year since he started tracking it. f is a sequence. what kind of sequence is it?
Number of leaves on the tree in first year = 500
The number of leaves was 40% more than the year before.
So rate of increase is 40/100 = 0.4
We use exponential growth formula,
f(n) = a(1+r)^n
Where a is the initial number, r is the rate of growth, n is the number of years
We know a= 500, r= 0.4
f(n) = 500(1+0.4)^n
f(n) = 500(1.4)^n
Plug in n=1,2,3...
f(1) = 500
f(2) = 500 * 1.4^1
f(3) = 500 * 1.4^2 and so on
From this we can see that the common ratio is 1.4
Hence it is a Geometric sequence.
Answer:
bout 7
Step-by-step explanation:
Answer:
1/6
Step-by-step explanation:
So we are subtracting a negative which is the same as adding. Our equation becomes -1/3+1/2. To add fractions we need a common denominator (the denominator of a fraction is the number on the bottom) To fine the least common denominator we need to find the lowest number that both 3 and 2 go into which is 6. Then we will multiply each fraction by the number that will give us 6 for a denominator which is 2 for -1/3 and 3 for 1/2. So -1/3 times 2 is -2/6 and 1/2 times 3 is 3/6. Our equation is now -2/6+3/6. Now we will add the numerators ( the numerator is the number on the top of the fraction) and the denominators stay the same when adding or subtraction fractions -2/6+3/6=1/6
I hope this helps and please let me know if there is anything you are confused about or is still unclear, I will be happy to help!
