Multiply the the numbers for each locket and see which number is greater
Answer:
The probability of selecting a family with exactly one male child is 1/4 or 0.25.
Step-by-step explanation:
Given in the question,
possible outcomes for the children's genders
{FFFF, FFFM, FFMF, FMFF, MFFF, MFFM, MFMF, MMFF, FFMM, FMFM, FMMF, FMMM, MFMM, MMFM, MMMF, MMMM}
= 16
To find,
the probability of selecting a family with exactly one male child
<h3>Probability = favourable outcomes / possible outcomes</h3>
favourable outcomes = {FFFM, FFMF, FMFF, MFFF}
= 4
Probability = 4 / 16
= 1 / 4
= 0.25
We know that
The triangle inequality<span> states that for any </span>triangle, t<span>he sum of the lengths of any two sides of a </span>triangle<span> is greater than the length of the third side
</span>so
case <span>A. 81 mm, 7 mm, 6 mm
6+7 is not > 81
case </span><span>B. 81 mm, 7 mm, 72 mm
72+7 is not > 81
case </span><span>C. 81 mm, 7 mm, 88 mm
81+7 is not > 88
case </span><span>D. 81 mm, 7 mm, 77 mm
81+7 is > 77------> ok
77+7 is > 81-----> ok
81+77 is > 7-----> is ok
the answer is the option
</span>D. 81 mm, 7 mm, 77 mm
Answer:
<h2>A. (0,1)</h2>
Step-by-step explanation:
The question lacks the e=required option. Find the complete question below with options.
Which of the following points does not belong to the quadratic function
f(x) = 1-x²?
a.(0,1) b.(1,0) c.(-1,0)
Let f(x) = 0
The equation becomes 1-x² = 0
Solving 1-x² = 0 for x;
subtract 1 from both sides;
1-x²-1 = 0-1
-x² = -1
multiply both sides by minus sign
-(-x²) = -(-1)
x² = 1
take square root of both sides;
√x² = ±√1
x = ±1
x = 1 and x = -1
when x = 1
f(x) = y = 1-1²
y = 1-1
y = 0
when x = -1
f(x) = y = 1-(-1)²
y = 1-1
y = 0
Hence the coordinate of the function f(x) = 1-x² are (±1, 0) i.e (1, 0) and (-1, 0). The point that does not belong to the quadratic function is (0, 1)
See attachment of the graph of the inequalities x + 7y ≤ 49 and 6x + y ≤ 48
<h3>How to graph the inequalities?</h3>
The inequalities are given as:
x + 7y ≤ 49
6x + y ≤ 48
The domain and the range are:
x ≥ 0
y ≥ 0
This means that, we plot the inequalities x + 7y ≤ 49 and 6x + y ≤ 48 under the domain and the range x ≥ 0 and y ≥ 0
See attachment of the graph of the inequalities x + 7y ≤ 49 and 6x + y ≤ 48
Read more about inequalities at:
brainly.com/question/25275758
#SPJ1