Answer:
Both boats will be 54 miles apart after 3 hours.
Step-by-step explanation:
Given that from a point on a river, two boats are driven in opposite directions, one at 7 miles per hour and the other at 11 miles per hour, to determine how many hours they will be 54 miles apart, the following calculation must be performed :
54 / (11 + 7) = X
54/18 = X
3 = X
Therefore, both boats will be 54 miles apart after 3 hours.
The answer is c)32 hope this helps
Sum of angles of a linear pair = 180. So angle with measurement 142 and the adjacent angle to it have a sum = 180.
THerefore 142+y=180
Subtracting 142 from both sides
y = 38
Now in the down right sides corner triangle
38+49+w=180
87+w=180
Subtracting 80 from both sides,
w = 93
So the measurement of angle w = 93 .
That's just too bad. I don't the answer. I'm just doing this to get points. Good luck.
Answer:
x = 2
Step-by-step explanation:
These equations are solved easily using a graphing calculator. The attachment shows the one solution is x=2.
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<h3>Squaring</h3>
The usual way to solve these algebraically is to isolate radicals and square the equation until the radicals go away. Then solve the resulting polynomial. Here, that results in a quadratic with two solutions. One of those is extraneous, as is often the case when this solution method is used.

The solutions to this equation are the values of x that make the factors zero: x=2 and x=-1. When we check these in the original equation, we find that x=-1 does not work. It is an extraneous solution.
x = -1: √(-1+2) +1 = √(3(-1)+3) ⇒ 1+1 = 0 . . . . not true
x = 2: √(2+2) +1 = √(3(2) +3) ⇒ 2 +1 = 3 . . . . true . . . x = 2 is the solution
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<h3>Substitution</h3>
Another way to solve this is using substitution for one of the radicals. We choose ...

Solutions to this equation are ...
u = 2, u = -1 . . . . . . the above restriction on u mean u=-1 is not a solution
The value of x is ...
x = u² -2 = 2² -2
x = 2 . . . . the solution to the equation
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<em>Additional comment</em>
Using substitution may be a little more work, as you have to solve for x in terms of the substituted variable. It still requires two squarings: one to find the value of x in terms of u, and another to eliminate the remaining radical. The advantage seems to be that the extraneous solution is made more obvious by the restriction on the value of u.