Question 18 4 pts Find f'(x). 1 f(x) 5x2 2 f'(x) = 583 1 f'(x) = 5x3 f'(x) = 2 5x 2 f(x) 5x3

Please give me the answers to all three I will mark u brilliant

elixir [45]

Answer:

First know the formula for the area of a circle;

Where 'π' represents pi(3.14 or 22/7), and 'r' stands for the radius being squared.

For the first problem, we can see that 12 is our diameter.

And to find the radius, we need to find 1/2 of the diameter (half of the diameter), so;

D/2 = R

Replace with actual values;

12/2 = 6, 6 is our radius.

Now we plug this into our formula:

A = π $r^{2}$

A = 3.14(6^2)

A = 3.14(36)

A = 113.04 centimetres is the area of the circle.

For the second problem, we can see that 18 is our diameter.

And to convert the diameter into the radius, we do what we did to the past problem, find 1/2 of the diameter.

So;

D/2 = R

18/2 = 9, 9 is our radius.

Now we plug this into our formula:

A = π $r^{2}$

A = 3.14(9^2)

A = 3.14(81)

A = 254.34 inches is the area for this circle.

For the third problem, we can see that our radius is already given, 5.

So now we just simply and easily plug this into our formula;

A = π $r^{2}$

A = 3.14(5^2)

A = 3.14(25)

A = 78.5 meters is the area for this circle.

4 0

2 years ago

Write the equation of the quadratic function in standard form represented by the graph

Nutka1998 [239]

Hello :
f(x) = a(x-k)²+k....... the point vertex is (h , k )
in this exercice : h = -3 and k = -1 s0 f(x) = a(x+3)²-1
find : a
but f(0)=8
a(0+3)² -1 = 8
9a-1=8
9a =9
a=1
f(x) =(x+3)²-1 =x²+6x+9-1
f(x) = x²+6x+8 .... (the quadratic function in standard form )

3 0

3 years ago

An item is regularly priced at $80 . It is on sale for 20% off the regular price. How much (in dollars) is discounted from the r

Mazyrski [523]

80 * .20=16

It is 16 dollars off the regular price

3 0

3 years ago

Function 1: y = 4x + 5

rosijanka [135]

Answer:

Option B is correct

Function 1, because the slope is 4 and the slope of function 2 is 2.

Step-by-step explanation:

Slope-intercept form:

The equation of line is given by:

$y=mx+b$

where, m is the slope and b is the y-intercept

As per the statement:

Function 1: y = 4x + 5

On comparing with [1] we have;

Slope of function 1 = 4

Function 2: The line passing through the points (1, 6) and (3, 10).

Using slope formula:

$\text{Slope}= \frac{y_2-y_1}{x_2-x_1}$

Substitute the given points we have;

$\text{Slope}= \frac{10-6}{3-1}$

⇒ $\text{Slope}= \frac{4}{2}$

Simplify:

⇒ $\text{Slope}=2$

⇒ $\text{Slope}= \frac{4}{2}$

⇒ Slope of the function 2 is, 2

Since, function 1 is greater rate of change.( i.e 4 > 2)

Therefore,

Function 1 has the greater rate of change, because the slope is 4 and the slope of function 2 is 2.

3 0

3 years ago

Read 2 more answers

If the dimensions of a pentagonal prism are quadrupled, then the surface area of the prism is multiplied by eight.

Lubov Fominskaja [6]

Answer:

false

Step-by-step explanation:

the relationship between lengths/dimensions and areas is that areas are created by multiplying 2 dimensions.

when you quadruple (×4) the dimensions, then the areas are growing with the square of the factor (×4×4 = ×16), because the factor goes twice into the multiplication : one time for every dimension involved.

so, quadrupling the dimensions would multiply the areas by 16.

8 0

3 years ago

Question 18 4 pts Find f'(x). 1 f(x) 5x2 2 f'(x) = 583 1 f'(x) = 5x3 f'(x) = 2 5x 2 f(x) 5x3​

Question 18 4 pts Find f'(x). 1 f(x) 5x2 2 f'(x) = 583 1 f'(x) = 5x3 f'(x) = 2 5x 2 f(x) 5x3