Question 18 4 pts Find f'(x). 1 f(x) 5x2 2 f'(x) = 583 1 f'(x) = 5x3 f'(x) = 2 5x 2 f(x) 5x3
1 answer:
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Answer:
x = 9
Step-by-step explanation:
Since the angle is bisected by rhe segment then the ratio of the sides to the corresponding parts of the base are equal, that is
=
( cross- multiply )
20x = 180 ( divide both sides by 20 )
x = 9
In the picture we can see the graph represents of the function f(x)=x²-2x+3 that is curve graph.
Given that,
We have to find the graph represents the function f(x)=x²-2x+3.
We know that,
The quadratic function is f(x)=x²-2x+3.
This is a vertical parabola open downward
The vertex is a maximum
We know,
A vertical parabola's equation in vertex form is equal to
y= a(x-h)²+k
where
a is a coefficient
(h,k) is the vertex
Here
a=1
(h,k)=(0,3) is vertex
The y-intercept is the point (0,3) is value of y when the value of x is equal to zero (is the same point that the vertex)
The x-intercepts are the points is values of x when the value of y is equal to zero
Therefore, In the picture we can see the graph represents of the function f(x)=x²-2x+3.
To learn more about function visit: brainly.com/question/9554035
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