Question 18 4 pts Find f'(x). 1 f(x) 5x2 2 f'(x) = 583 1 f'(x) = 5x3 f'(x) = 2 5x 2 f(x) 5x3
1 answer:
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The solution to the quadratic equation are option C) x= -5 and option E) x=3.
<u>Step-by-step explanation</u>:
The given quadratic equation is x²+2x-15 = 0.
Using the factorization method,
- product of the roots should be -15.
- Sum of the roots should be 2.
⇒ -15 = 5 -3
⇒ 2 = 5+(-3)
(x+5)(x-3) = 0
Therefore, x = -5 and x = 3
If the diameter of the cylinder's base is 10, then the radius is half that, or 5.
