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xxTIMURxx [149]
3 years ago
13

If a test is worth 90 points and I got 12/15 questions right then what would my grade be?

Mathematics
1 answer:
Yuki888 [10]3 years ago
6 0

Answer: 80

Step-by-step explanation:

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given a system of equations, list three ways that we can write new equations that can be used to create equivalent systems
cupoosta [38]

Answer:

See explanation

Step-by-step explanation:

Given a system of equations, you can

  • rewrite one of the equations and write the sum of two equations instead of the second equation;
  • rewrite one of the equations and write the difference of two equations instead of the second equation;
  • rewrite one of the equations and write the sum of the first equation multiplied by one nonzero number and the second equation multiplied by another nonzero number instead of the second equation.

These actions are called elementary row operations. Elementary operations with system of equations do not change the solution set.

4 0
3 years ago
10 x 3 tens - unit form and standard form
vfiekz [6]
<span>10X3 tens in unit form is written:
10*3 tens = 30 tens = 300 units

10X3 tens in standard form:
10 x 3 tens = 10 x 30 = 300</span>
6 0
3 years ago
Read 2 more answers
I’m slow , can i get help on this asap please ?
makkiz [27]
140°
Pentagons add up to 540° so if you add all the degrees you get 400° and if subtracted from 540° you get 140°
5 0
3 years ago
Jason states that Triangle A B C is congruent to triangle R S T. Kelley states that Triangle A B C is congruent to triangle T S
Brilliant_brown [7]

Answer:

The correct option is;

Jason's statement is correct. RST is the same orientation, shape, and size as ABC

Step-by-step explanation:

Here we have

ABC = (2, 1), (3, 3), (4, 1)

RST = (-4, -2), (-3, 0), (-2, -2)

Therefore the length of the sides are as follows

AB = \sqrt{(2-3)^2+(1-3)^2} = \sqrt{5}

AC = \sqrt{(2-4)^2+(1-1)^2} =2

BC = \sqrt{(3-4)^2+(3-1)^2} = \sqrt{5}

For triangle SRT we have

RS = \sqrt{(-4-(-3))^2+(-2-0)^2} = \sqrt{5}

RT = \sqrt{(-4-(-2))^2+(-2-(-2))^2} = 2

ST = \sqrt{(-3-(-2))^2+(0-(-2))^2} = \sqrt{5}

Therefore their dimensions are equal

However the side with length 2  occurs between (2, 1) and (4, 1) in triangle ABC and between (-4, -2) and (-2, -2) in triangle RST

That is Jason's statement is correct. RST is the same orientation, shape, and size as ABC.

4 0
3 years ago
Read 2 more answers
What is the y-intercept of the quadratic function f(x) = (x – 8)(x + 3)? (8,0) (0,3) (0,–24) (–5,0)
DiKsa [7]
The correct answer is:  [C]:  " (0, 24) " .
___________________________________________________________

Explanation:
___________________________________________________________

Given the quadratic function:
___________________________________________________________

          →  "  y = (x <span>− 8) (x + 3) "  ;   </span>←  Note:  Replace the "f(x)" with: "y" ; 

→  Find the "y-intercept".
___________________________________________________________

→  Note:  The "y-intercept" is the coordinate of the point(s) of the graph of the equation at which the graph crosses the "x-axis" when "x = 0" . 

   → So;  we set plug in "0" for "x" into our equation; and solve for "y" ; 

          → " y = (x − 8) (x + 3) " ;

          →   y = (0 − 8) (0 + 3)  ; 

          →   y = (-8) * (3)  ;  
 
          →   y = - 24 ; 
___________________________________________________________

So, the "y -intercept" of the <em><u>given</u></em> quadratic function is:
 
the point at which:  "x = 0 ; y = -24 " ;

      →  that is; the point  the coordinates:  " (0, - 24) " ;
___________________________________________________________
  →  which is:  Answer choice:  [C]:  " (0, - 24) " .
___________________________________________________________
9 0
3 years ago
Read 2 more answers
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