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xxTIMURxx [149]
2 years ago
13

If a test is worth 90 points and I got 12/15 questions right then what would my grade be?

Mathematics
1 answer:
Yuki888 [10]2 years ago
6 0

Answer: 80

Step-by-step explanation:

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Airplanes approaching the runway for landing are required to stay within the localizer (a certain distance left and right of the
Arisa [49]

Answer:

a) P(x = 0) = 64.69%

b) P(x ≥ 1) = 35.31%

c) E(x) = 0.42

d) var(x) = 0.3906

Step-by-step explanation:

The given problem can be solved using binomial distribution since:

  • There are n repeated trials independent of each other.
  • There are only two possibilities: exceedence happens or  exceedence doesn't happen.
  • The probability of success does not change with trial to trial.

The binomial distribution is given by

P(x) = ⁿCₓ pˣ (1 - p)ⁿ⁻ˣ

Where n is the number of trials, x is the variable of interest and p is the probability of success.

For the given scenario. the six daily arrivals are the number of trials

Number of trials = n = 6

The probability of success = 7% = 0.07

a) Find the probability that on one day no planes have an exceedence.

Here we have x = 0, n = 6 and p = 0.07

P(x = 0) = ⁶C₀(0.07⁰)(1 - 0.07)⁶⁻⁰

P(x = 0) = (1)(0.07⁰)(0.93)⁶

P(x = 0) = 0.6469

P(x = 0) = 64.69%

b) Find the probability that at least 1 plane exceeds the localizer.

The probability that at least 1 plane exceeds the localizer is given by

P(x ≥ 1) = 1 - P(x < 1)

But we know that P(x < 1) = P(x = 0) so,

P(x ≥ 1) = 1 - P(x = 0)

We have already calculated P(x = 0) in part (a)

P(x ≥ 1) = 1 - 0.6469

P(x ≥ 1) = 0.3531

P(x ≥ 1) = 35.31%

c) What is the expected number of planes to exceed the localizer on any given day?

The expected number of planes to exceed the localizer is given by

E(x) = n×p

Where n is the number of trials and p is the probability of success

E(x) = 6×0.07

E(x) = 0.42

Therefore, the expected number of planes to exceed the localizer on any given day is 0.42

d) What is the variance for the number of planes to exceed the localizer on any given day?

The variance for the number of planes to exceed the localizer is given by

var(x) = n×p×q

Where n is the number of trials and p is the probability of success and q is the probability of failure.

var(x) = 6×0.07×(1 - 0.07)

var(x) = 6×0.07×(0.93)

var(x) = 0.3906

Therefore, the variance for the number of planes to exceed the localizer on any given day is 0.3906.

6 0
3 years ago
a distribution for the last difit of phone numbers sampled from a phone book for the phone number 968-9667 the last difit 7 woul
lisov135 [29]

Answer:

The answer is "Option D".

Step-by-step explanation:

Please find the attached file of the complete question:

In this question, the last choice "Histogram IV" is correct because it would be roughly evenly distributed.

7 0
2 years ago
The bookstore has six red school jerseys, five blue school jerseys, and ten green school jerseys to choose from. If a student se
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3 0
3 years ago
What is .4 as a fraction
Dmitriy789 [7]
2/5 is .4 as a fraction
7 0
2 years ago
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Leyla drops a penny from a height of 150 m.
gizmo_the_mogwai [7]
When the penny hits the ground, h will = 0.

So:  Set h(t) = 0 = -4.9t^2 + 0t + 150 m

Then 4.9t^2 = 150, and so t^2 = sqrt(150 / 4.9)   =    plus or minus 5.53 sec.

We can use only the positive root, as we're measuring time.

t = 5.5 sec (answer)
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