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MrRa [10]
3 years ago
10

Identify the process used to form the covalent peptide bonds that join amino acids into a polypeptide.

Biology
1 answer:
timama [110]3 years ago
7 0

Answer:

Condensation reaction

Explanation:

Covalent peptide bond is formed between two amino acids. It is formed by condensation reaction which is also called as dehydration synthesis reaction. One molecule's carboxyl group reacts with other molecule's amino group releasing a water molecule. This CO-NH bond is called as peptide bond or amide bond and an amide molecule is formed as a result.

An amide bond shows resonance which allows its stabilization and versatility of molecule in different environment. The amino acids link together via condensation reaction to form larger polypeptide chains.

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Why is osmosis important to the survival of a cell?Why is osmosis important to the survival of a cell?
denis23 [38]

Hello good afternoon...God bless :) here is the answer to your following question...

Explanation:

Osmosis is important to cells because it allows them to maintain water homeostasis. The most important function of osmosis is stabilising the internal environment of an organism by keeping the water and intercellular fluids levels balanced. In all living organisms, nutrients and minerals make their way to the cells because of osmosis. This obviously is essential to the survival of a cell.

4 0
3 years ago
Read 2 more answers
Which of these is the reasons organisms perform photosynthesis?
IrinaVladis [17]

Answer:

Plants perform photosynthesis to produce glucose.

Explanation:

Glucose is used by plants for energy and to make other substances like cellulose and starch.

5 0
3 years ago
Read 2 more answers
Explain the electron transfer chain
Sonja [21]

Answer:

The electron transport chain is a cluster of proteins that transfer electrons through a membrane to create a gradient of protons that creates ATP (adenosine triphosphate) or energy that is needed in metabolic processes for cellular function.

Thanks

8 0
3 years ago
Alkaptoneuria is a recessive genetic disorder found among North American populations at a frequency of about 1 in 500,000 births
Dafna11 [192]

Answer:

The correct answer is - 1/41,493

Explanation:

Let assume the frequency of the two possible same allele genotype (dominant and recessive) in an inbred population is p and q. Then the frequency of heterozygotes (H) is denoted as:

2pq + 2pqF.  ( where F is the inbreeding coefficient).

The frequency of the two different hoozygotes in inbred population can be calculated as:

p2 + pqF and q2 + pqF. (Where p and q are the allele frequency of the dominant and recessive phenotype.

Given: Frequency of Alkaptonuria (q 2) = 1:500, 000

=> q = 1/707

p = 706/707 ( Approx values)

solution:

Inbreeding coefficient (F) = 1/64

Therefore,

Frequency of Alkaptonuria in second cousins= q 2 + pqF

= 1/500, 000 + (706/707 x 1/707) x (1/64)

= 1/500, 000 + 1/45, 248

= 1/41,493 (approx)

5 0
3 years ago
I need help figuring this out. Please
defon

Answer:

1) G C G U A U G (C C C) (U U U) (A A C) (C G C)

2) U U A U G (C G U) (U A G) (G C G) (U U U) (A U U)

3) U A U G (G C U) (U A G)  (A A U) (A A C) (C C G) (U A A)

4) U U A U G (C A A) (A G G) (G C G) (U A U) (C U U) (U A G)

5) represent codons which are groupings of 3 consecutive nucletides

Explanation:

Opposites for REGULAR mDNA base pairings are T= A  and G = C, however, since it is mRNA, your base pairings change a little. G is still to C BUT Thymine (T) becomes Uracil (U) so A= U instead of A= T.  So big difference between mRNA and mDNA is that Thymine changes to Uracil and vice versa depending on how the code is being translated.

Hope this helps some, please let me know if there's anything that doesn't make sense

8 0
2 years ago
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