Answer:
b. False
Explanation:
FOXP2 gene is required for language and speech development and is present in all animals. It is a transcription factor which encodes for a regulatory protein. Both modern humans and Neanderthals share FOXP2 gene which differs from chimpanzee version by two amino acids. Its the different regulation of the same gene which made modern humans more capable of using language and speech. Neanderthals did use language rudiments but not completely constructed languages. There might be other speech genes involved too which differed between modern day humans and Neanderthals but not FOXP2.
Answer:
When diverse molecules and objects are brought together, they generate a chemical, which causes sickness. Forest fires can occur spontaneously or as a result of human activity. Natural factors include severe droughts and a lack of precipitation. Campfires or the usage of a flare gun can be used to create man-made causes.
Viruses are not made out of cells, they can't keep themselves in a stable state, they don't grow, and they can't make their own energy. Even though they definitely replicate and adapt to their environment, viruses are more like androids than real living organisms.
Answer:
2% of the progeny will be double crossovers for the trihybrid test cross
Explanation:
By knowing the positions of genes, we can estimate the distances in MU between them per region.
- Genes A and B are 10 map units apart (Region I)
- Genes B and C are 20 map units apart (Region II)
- Genes A and C are 30 map units apart
----A-------10MU--------B-------------20MU-------------C---
Region I Region II
We can estimate the recombination frequencies by dividing each distance by 100.
• recombination frequency of A-B region = 10MU / 100 = 0.10
• recombination frequency of B-C region = 20MU / 100 = 0.20
Now that we know the recombination frequencies in each region, we can calculate the expected double recombinant frequency, EDRF, like this:
EDRF = recombination frequency in region I x recombination frequency in region II.
EDRF = 0.10 x 0.20 = 0.02
2% of the progeny will be double crossovers for the trihybrid test cross