Answer:
See verification below
Step-by-step explanation:
Remember that the Intermediate Value Theorem (IVT) states that if f is a continuous function on [a,b] and f(a)<M<f(b), there exists some c∈[a,b] such that f(c)=M.
Now, to apply the theorem, we have that f(0)=0²+0-1=-1, f(5)=5²+5-1=29, then f(0)=-1<11<29=f(5). Additionally, f is continous since it is a polynomial. Then the IVT applies, and such c exists.
To find, c, solve the quadratic equation f(c)=11. This equation is c²+c-1=11. Rearranging, c²+c-12=0. Factor the expression to get (c+4)(c-3)=0. Then c=-4 or c=3. -4 is not in the interval, then we take c=3. Indeed, f(3)=3²+3-1=9+3-1=11.
Answer:
x+5>-7
Step-by-step explanation:
The sum of a number and five translates to x+5. It then states that this expression is more than negative seven, therefore you use a greater than sign to get x+5>-7
Answer:
6/5
Step-by-step explanation:
brainly plz
but if one whole is 5 then one has 5 and the other has 1 and 5+1=6 and one whole=5 thus is 6/5
Answer:
1,495
Step-by-step explanation:
16,400
- 1,500
+ 50
--------------
14,950
14,950/10
Answer:
1. Not a function.
2. This is a function.
3. This is a function.
Step-by-step explanation:
1. 13 maps on to 4 and -4 so not a function.
2 and 3 - these both pass the vertical line test so they are functions.
