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Ostrovityanka [42]

2 years ago

9

I will give u 100 points and mark you as brainiest if you can answer this for me pls I need it I am in a quiz Order –17, –14, an

d 6 from greatest to least. –17, –14, 6 –14, 6, –17 6, –17, –14 6, –14, –17

2 answers:

Dafna1 [17]2 years ago

4 0

Answer:

-17-17,-17,-17,-14,-14,-14,-14,6,6,6,6

Step-by-step explanation:

hope it helped.

dsp732 years ago

3 0

Greatest - 6 Middle - -14 Least - -17

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A survey was conducted in the United Kingdom, where respondents were asked if they had a university degree. One question asked,

katovenus [111]

Answer:

$z=\frac{0.121-0.0892}{\sqrt{0.101(1-0.101)(\frac{1}{373}+\frac{1}{639})}}=1.620$

$p_v =2*P(Z>1.620)=0.105$

If we compare the p value and using any significance level for example $\alpha=0.05$ always $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the two proportions are not statistically different at 5% of significance

Step-by-step explanation:

Data given and notation

$X_{1}=45$ represent the number of correct answers for university degree holders

$X_{2}=57$ represent the number of correct answers for university non-degree holders

$n_{1}=373$ sample 1 selected

$n_{2}=639$ sample 2 selected

$p_{1}=\frac{45}{373}=0.121$ represent the proportion of correct answers for university degree holders

$p_{2}=\frac{57}{639}=0.0892$ represent the proportion of correct answers for university non-degree holders

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the proportions are different between the two groups, the system of hypothesis would be:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{45+57}{373+639}=0.101$

Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.121-0.0892}{\sqrt{0.101(1-0.101)(\frac{1}{373}+\frac{1}{639})}}=1.620$

Statistical decision

For this case we don't have a significance level provided $\alpha$ , but we can calculate the p value for this test.

Since is a one side test the p value would be:

$p_v =2*P(Z>1.620)=0.105$

If we compare the p value and using any significance level for example $\alpha=0.05$ always $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the two proportions are not statistically different at 5% of significance

7 0

2 years ago

Given that <br> y<br> = 10 cm and <br> θ<br> = 55°, work out <br> x<br> rounded to 1 DP.

ElenaW [278]

Answer:

x=8.2

Step-by-step explanation:

First, figure out which trig function you are going to use.

In this problem you are dealing with the opposite side to the angle and the hypotenuse, and if you remember SOH CAH TOA, this requires sine.

sin (55) =opposite/hypotenuse

sin (55) =x/10

multiply both sides by 10 to get 10 * sin (55) = x

10 * sin (55) = 8.2

5 0

2 years ago

How many real sixth roots are in 15,625?

Murljashka [212]

There are two real roots (5 and -5) and 4 imaginary roots

3 0

3 years ago

#2 Find the segment length indicated. Assume that lines which appear to be tangent are tangent. *

gregori [183]

The angle of a tangent and a radius is a right angle.

The missing length would be the hypotenuse. Use the Pythagorean theorem to solve.

X = SQRT(12^2 + 16^2)

X = SQRT(144 + 256)

x = SQRT(400)

X = 20

4 0

3 years ago

4 consecutive integers add up to 34. Write an equation to find the numbers

Kisachek [45]

Answer:

$(n+(n+1)+(n+2)+(n+3))=34$

Step-by-step explanation:

$(n+(n+1)+(n+2)+(n+3))=34$

To make them consecutive, means they have to be one after the other.
You assume one of the numbers are n, to make the other integers consecutive you add 1 then 2 then 3.

4 0

1 year ago