Answer:
The correct answer is - option C.
Explanation:
CFTR is a short form of cystic fibrosis transmembrane conductance regulator protein which is caused by a recessive mutation in this protein. This mutation results in the accumulation of mucus in secretory organs.
As the disease is a recessive disease, for the mutant phenotype to expressed both copies of the allele required to be recessive.
The mother is negative for the CFTR. Hence, she will not transfer the mutant allele to her child So, the child would have a wild-type phenotype even if the father having two copies of recessive allele.
Thus, the correct answer is - option C.
<span>1) regulation of enzyme activity. 2) regulation of enzyme production.</span>
<span>At the end of meiosis II, compared to the DNA from the original cell, the DNA in each of the four new cells is C)half as much and genetically different from the original. Meiosis is the type of cell division in which the genetic material is reduced by half. Thus, choices B and D are incorrect. Further, the exchange of genetic material between homologous chromosomes so-called the crossover occurs during meiosis, so DNA in new cells will be genetically different from the original DNA. Thus, the correct choice is C.</span>
A. knowledge of the enviroment.
