If we assume the given segments are those from the vertices to the point of intersection of the diagonals, it seems one diagonal (SW) is 20 yards long and the other (TR) is 44 yards long. The area (A) of the kite is half the product of the diagonals:
... A = (1/2)·SW·TR = (1/2)·(20 yd)·(44 yd)
... A = 440 yd²
Answer:
Step-by-step explanation:
<u>Given data:</u>
Base = b = 4 cm
Height = h = 4 cm
<u>Required:</u>
Area of triangle = A = ?
<u>Formula:</u>
A = bh / 2
<u>Solution:</u>
A = (4)(4) / 2
A = 16 / 2
A = 8 cm²
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Answer:
Perimeter = 34ft Area = 72ft squared
Step-by-step explanation:
The perimeter of an object is all of it's sides combined. Because you stated two values, I assumed your shape is a rectangle. So the perimeter would be:
8 + 8 + 9 + 9 = 34
The area is length times width, so:
8 x 9 = 72
Because it is area, the units are squared.
Answer:
1/3
Step-by-step explanation:
For each term multiply each number to see what value you get, only 1/3 makes sense
18 x 1/3 =6
6 x 1/3= 2
