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Rashid [163]
3 years ago
6

Help: 10 points!! 13=n+ 3/fourths

Mathematics
1 answer:
disa [49]3 years ago
6 0

Answer:

n = 12 1/4

Step-by-step explanation:

do you need me to explain it too? I can! XD ^_^

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Given the Trapezoid ABCD<br><br> Find the length of AD <br><br> Pls hellpppp
matrenka [14]

Given:

In trapezoid ABCD, AD\parallel BC, MN is the mid-segment of ABCD, AD=30x-10,MN=31x+1,BC=30x+28.

To find:

The length of AD.

Solution:

We know that the length of the mid-segment of a trapezoids is half of the sum of lengths of two parallel sides of the trapezoid.

In trapezoid ABCD,

MN=\dfrac{AD+BC}{2}

31x+1=\dfrac{30x-10+30x+28}{2}

31x+1=\dfrac{60x+18}{2}

31x+1=30x+9

Isolate variable terms.

31x-30x=9-1

x=8

Now,

AD=30x-10

AD=30(8)-10

AD=240-10

AD=230

Therefore, the length of AD is 230.

6 0
3 years ago
Mr castle shares out 64 marbles between emily and asif in the ratio 7:1 how many marbles does each child get
Novay_Z [31]

Answer:

<h2>Emily: 72 marbles</h2><h2>Asif: 8 marbles</h2>

<em>Step-by-step explanation:</em>

first lets find in how many shares is the total amount of marbles divided into:

7+1=8

now, lets find how many marbles are in each share:

64/8=8

now that we know that each share of marbles contains 8 marbles, we can find how many each child got:

Emily got 7 shares: 8*7= 72 marbles

Asif got 1 share: 8*1= 8 marbles

Hence,

<h3><em>Emily got 72 marbles, while Asif got 8 marbles</em></h3>
7 0
3 years ago
Find x, y, z please help!
ki77a [65]

Answer:

x is 1 y is 1 and a is 1 hope this helped

6 0
3 years ago
Please solve for me. C=1/2x(a+w)
Gnoma [55]

Answer:

C= 1/(2ax+2aw)

Step-by-step explanation:

C=1/2x(a+w)

Multiply a and w by 2x. Take note of the sign.

C= 1/(2ax+2aw)

when writing your answer, you don't need the brakets. I just put them so you'd understand that all those characters in the bracket are the denominator.

Please rate 5 stars, thanks, give brainliest. Thanks.

5 0
3 years ago
Read 2 more answers
Two streets bounding your triangular lot make an angle of 74∘. The lengths of the two sides of the lot on these streets are 126
ycow [4]

Answer: a) Yes, there is enough fance

b) 58.1° and 47.9°

c) The city will not approve, because 1/3 of the area is just 2220.5ft²

Step-by-step explanation:

a) using law of cosines: x is the side we do not know.

x² = 126² + 110² - 2.126.110.cos74°

x² = 20335.3

x = 142.6 ft

So 150 > 142.6, there is enough fance

b) using law of sine:

sin 74/ 142.6 = sinα/126 = sinβ/110

sin 74/ 142.6 = sinα/126

0.006741 = sinα/126

sinα = 0.849

α = sin⁻¹(0.849)

α = 58.1°

sin 74/ 142.6 = sinβ/110

sin 74/ 142.6 = sinβ/110

0.006741 = sinβ/110

sinβ = 0.741

β = sin⁻¹(0.741)

β = 47.9°

Checking: 74+58.1+47.9 = 180° ok

c) Using Heron A² = p(p-a)(p-b)(p-c)

p = a+b+c/2

p=126+110+142.6/2

p=189.3

A² = 189.3(189.3-126)(189.3-110)(189.3-142.6)

A = 6661.5 ft²

1/3 A = 2220.5

So 2300 >  2220.5. The area you want to build is bigger than the area available.

The city will not approve

7 0
3 years ago
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