If general form means y=mx+b form then your answer would be B
F(2)= 4(16) - 6(4) + 8(2) - 15
F(2)= 64 -24 + 16 - 15
F(2)= 41
You would need a new y-intercept in order for this to be parallel. So you use the points given and the slope and fill it in. 3=-5(-6)+b. 3=30+b. Then subtract 30 from both sides. -27=b. Then just put it all back into slope intercept form. y=-5x-27.
The function, as presented here, is ambiguous in terms of what's being deivded by what. For the sake of example, I will assume that you meant
3x+5a
<span> f(x)= ------------
</span> x^2-a^2
You are saying that the derivative of this function is 0 when x=12. Let's differentiate f(x) with respect to x and then let x = 12:
(x^2-a^2)(3) -(3x+5a)(2x)
f '(x) = ------------------------------------- = 0 when x = 12
[x^2-a^2]^2
(144-a^2)(3) - (36+5a)(24)
------------------------------------ = 0
[ ]^2
Simplifying,
(144-a^2) - 8(36+5a) = 0
144 - a^2 - 288 - 40a = 0
This can be rewritten as a quadratic in standard form:
-a^2 - 40a - 144 = 0, or a^2 + 40a + 144 = 0.
Solve for a by completing the square:
a^2 + 40a + 20^2 - 20^2 + 144 = 0
(a+20)^2 = 400 - 144 = 156
Then a+20 = sqrt[6(26)] = sqrt[6(2)(13)] = 4(3)(13)= 2sqrt(39)
Finally, a = -20 plus or minus 2sqrt(39)
You must check both answers by subst. into the original equation. Only if the result(s) is(are) true is your solution (value of a) correct.
Answer:
3.9
Step-by-step explanation:
(76-62.10)÷3.55=3.91...
=3.9 (correct to nearest tenth)
