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Irina-Kira [14]
3 years ago
13

The grocery store sells kumquats for $5.00 a pound and Asian pears for $3.25 a pound. Write an equation in standard form for the

weights of kumquats k and Asia pears p that a customer could buy with $18
Mathematics
2 answers:
Vsevolod [243]3 years ago
8 0

Answer:

Equation will be 5k + 3.25p = $18

Step-by-step explanation:

Price of kumquats per pound = $5.00

Price of Asian pears per pound = $3.25

Let the weight of kumquats be represented by = k

Let the weight of Asian pears be represented by = p

As asked, how much kumquats and pears can be bought in $18

The equation will be 5k + 3.25p = $18

aniked [119]3 years ago
3 0
Okay so your equation is going to be : 18= 5k + 3.25p
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Answer:

But the graph paper is not here...

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2 years ago
Plz help!! Will give 30 points!!
Inessa [10]

Answer:

B) 12

Step-by-step explanation:

C is the circumference, d is the diameter, and r is the radius.  They are related by the following equations:

d = 2r

C = πd = 2πr

If d = 6.0, then r = 3.0.

If C / C' = 0.25, then:

(2πr) / (2πr') = 0.25

r / r' = 0.25

3 / r' = 0.25

r' = 12

8 0
3 years ago
Read 2 more answers
Explain how to find the estimated sum of 5/8+2/9 . Make sure to include at least one type of model.
OverLord2011 [107]
In this expression you would have to use the PEMDAS method. First divide, so (5 divided by 8) + (2 divided by 9). 
The answer you would get is: (0.625) + (0.222)
The final answer is: 0.847

8 0
3 years ago
The total cost (in hundreds of dollars) to produce x units of a product is c(x) = (3x-2) / (8x+1), find the average cost for eac
olya-2409 [2.1K]

Answer:

a) \frac{74}{10025}

b) \frac{3x-2}{x(8x+1)}

c) \frac{-24x^2+32x-2}{(8x^2+x)^2}

Step-by-step explanation:

For total cost function c(x), average cost is given by \frac{c(x)}{x} i.e., total cost divided by number of units produced.

Marginal average cost function refers to derivative of the average cost function i.e., \left ( \frac{c(x)}{x} \right )'

Given:c(x)=\frac{3x-2}{8x+1}

Average cost = \frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}

a)

At x = 50 units,

\frac{c(50)}{50}=\frac{150-2}{50(400+1)}=\frac{148}{50(401)}=\frac{74}{10025}

b)

Average cost = \frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}

c)

Marginal average cost:

Differentiate average cost with respect to x

Take f=3x-2\,,\,g=8x^2+x

using quotient rule, \left ( \frac{f}{g} \right )'=\frac{f'g-fg'}{g^2}

Therefore,

\left ( \frac{c(x)}{x} \right )'=\left ( \frac{3x-2}{8x^2+x} \right )'\\=\left ( \frac{3(8x^2+x)-(16x+1)(3x-2)}{(8x^2+x)^2} \right )\\=\frac{24x^2+3x-48x^2-3x+32x+2}{(8x^2+x)^2}\\=\frac{-24x^2+32x-2}{(8x^2+x)^2}

3 0
3 years ago
What is the value of the expression?
user100 [1]
3a= 3(5) = 15
15 - - 3 = 15+3 = 18
18/6 = 3
b + a = 5 + -3 = -3 + 5 = 2
3 x 2 = 6
4 0
3 years ago
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