If the earth's population reached 1 billion humans in 1800, how many years would it take to double to 2 billion?

1 answer:

6 0

It really depends. If the population size was a constant rate, then it would be 3600, but population isn't constant, so it's hard to say, because of increases and decreases of population

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What is the distance between the points

kvv77 [185]

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A shopper purchased 4 tables and 2 chairs for $200 and 2 tables and 7 chairs for $400. What is the cost of each table and each c

I am Lyosha [343]

4t+2c=200
2t+7c=400

I will solve for c in terms of t first
4t+2c=200
2c=200-4t
c=100-2t

Then I will substitute this in for c in the second equation to make it single variable
2t+7c=400
2t+7(100-2t)=400
2t+700-14t=400
300t=12
t=25
Tables cost $25 each

Plug t back into one of the ORIGINAL equations to find the cost of chairs
4(25)+2c=200
100+2c=200
2c=100
c=50
Chairs cost $50 each

Hope this helps! :)

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4 years ago

What is the simplest form of 4/3

Ivanshal [37]

Answer:

43 is already in the simplest form. It can be written as 1.333333 in decimal form (rounded to 6 decimal places).

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3 years ago

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Describe the number 52 in two ways

TiliK225 [7]

Divisible by 2 and a even number

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can someone please help and explain to me on how to do this geometry question please?! Thank youuuuu!!! ❤

qaws [65]

There are 13 angles.
We know that $m\angle4=112$ and $m\angle12=105$ (11 angles)

1.

$m\angle2+m\angle3+m\angle4=180\qquad\qquad\text{linear angles}\\\\m\angle3+m\angle3+m\angle4=180\qquad\qquad m\angle2=m\angle3\\\\2m\angle3+m\angle4=180\\\\2m\angle3+112=180\\\\2m\angle3=180-112\\\\2m\angle3=68\quad|:2\\\\\boxed{m\angle3=34=m\angle2}$

(9 angles)

2.

$m\angle3+m\angle12+m\angle11=180\qquad\qquad\text{triangle}\\\\34+105+m\angle11=180\\\\139+m\angle11=180\\\\m\angle11=180-139\\\\\boxed{m\angle11=41}$

(8 angles)

3.

$m\angle12+m\angle13=180\qquad\qquad\text{linear angles}\\\\105+m\angle13=180\\\\m\angle13=180-105\\\\\boxed{m\angle 13=75}$

(7 angles)

4.

$m\angle1+m\angle2+m\angle13=180\qquad\qquad\text{triangle}\\\\m\angle1+34+75=180\\\\m\angle1+109=180\\\\m\angle1=180-109\\\\\boxed{m\angle1=71}$

(6 angles)

5.

$m\angle9=m\angle11\qquad\qquad\text{vertical angles}\\\\\boxed{m\angle9=41}$

(5 angles)

6.

$m\angle10+m\angle11=180\qquad\qquad\text{linear angles}\\\\m\angle10+41=180\\\\m\angle10=180-41\\\\\boxed{m\angle10=139}$

(4 angles)

7. $a||b\text{ and } c||d$ so we have a parallelogram.

$m\angle4+m\angle5=180\qquad\text{consecutive angles are supplementary}\\\\112+m\angle5=180\\\\m\angle5=180-112\\\\\boxed{m\angle5=68}$

(3 angles)

$m\angle8=m\angle5\qquad\qquad\text{opposite angels are congruent}\\\\\boxed{m\angle8=68}$

(2 angles)

8.

$m\angle7+m\angle8+m\angle9=180\qquad\qquad\text{triangle}\\\\m\angle7+68+41=180\\\\m\angle7+109=180\\\\m\angle7=180-109\\\\\boxed{m\angle7=71}$

(1 angle)

9.

$m\angle1+m\angle5+m\angle6=180\qquad\qquad\text{triangle}\\\\71+68+m\angle6=180\\\\139+m\angle6=180\\\\m\angle6=180-139\\\\\boxed{m\angle6=41}$

6 0

3 years ago