I believe the answer is 28.18
Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
Answer: -2, 0, 1, 3
Step-by-step explanation:
when you multiply -7 and -6 by -5 than add 5 you get a higher number than 25.
when you multiply -2, 0, 1 And 3 by -5 than add 5 you get a lower number than 25.
Answer: B
Step-by-step explanation:
l = 2
2 ( l + w ) = 48 , or , l + w = 24
w = 8 , & , so , l = 2 w = 16 inches.
