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DanielleElmas [232]
4 years ago
9

What is the answer to this geometry problem

Mathematics
1 answer:
Marizza181 [45]4 years ago
6 0
Because we were not given any specific point to start off with. I choose (2,2), which is shown in red as 1.

We translate it 2 times.
a) (x+5)(y+3) = (2+5)(2+3) = (7,5) is our new point (shown in brown as 2)
     Translation process shown in yellow.

b) (x-4)(y+2) = (7-4)(5+2) = (3,7) is our final point (shown in orange as 3)
    Note that we use the 2nd point for the second translation as required.
    Translation process shown in lime.

We can therefore determine from the picture below that you can use the translation (x+1)(y+5), which the translation process is shown in blue.
Proof: (x+1)(y+5) = (2+1)(2+5) = (3,7)

Now let's do it again, except we do the second translation first and the first translation last.

c) (x-4)(y+2) = (2-4)(2+2) = (-2,4) is our new point (shown in purple as 4)
    Translation process shown in pink.

d) (x+5)(y+3) = (-2+5)(4+3) = (3,7) is our final point (shown in orange as 3)
    Translation process shown in dark blue.
    Same rules as (b). Notice how the final point is still the same? Therefore it     makes no difference.

Hope I helped a lot :P

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A Halloween trick-or-treat group consists of 3 Trolls, 4 Nazguls, 4 Ents, and 5 Pokemon. A committee of 4 is to be picked to rep
balu736 [363]

Answer:

The probability that the committee will consist of 1 from each type of monster is 0.1318 and Suppose that the Pokemon refuse to be on the same committee as a the Trolls.So,the probability that this type of committee is formed is 0.5357        

Step-by-step explanation:

No. of Trolls = 3

No. of  Nazguls =4

No. of Ents = 4

No. of Pokemon = 5

Total Monsters = 16

We are given that A committee of 4 is to be picked to represent the group at the Monster Bash.

(a) Find the probability that the committee will consist of 1 from each type of monster.

So, the probability that the committee will consist of 1 from each type of monster:

= \frac{^3C_1 \times ^4C_1 \times ^4C_1 \times ^5C_1}{^{16}C_4}

= \frac{\frac{3!}{1!(3-1)!} \times \frac{4!}{1!(4-1)!} \times \frac{4!}{1!(4-1)!}\times \frac{5!}{1!(5-1)!}}{\frac{16!}{4!(16-4)!}}

= \frac{\frac{3!}{1!(2)!} \times \frac{4!}{1!(3)!} \times \frac{4!}{1!(3)!}\times \frac{5!}{1!(4)!}}{\frac{16!}{4!(12)!}}

= 0.1318

b)Suppose that the Pokemon refuse to be on the same committee as a the Trolls.

So,  the probability that this type of committee is formed

= \frac{(^3C_3 \times ^8C_1)+(^3C_2 \times ^8C_2)+(^3C_1 \times ^8C_3)+(^3C_0 \times ^8C_4)+(^5C_4 \times ^8C_0)+(^5C_3 \times ^8C_1)+(^5C_2 \times ^8C_2)+(^5C_1 \times ^8C_3)}{^{16}C_4}

= \frac{(\frac{3!}{3!(3-3)!} \times \frac{8!}{1!(8-1)!})+(\frac{3!}{2!(3-2)!} \times\frac{8!}{2!(8-2)!})+(\frac{3!}{1!(3-1)!} \times\frac{8!}{3!(8-3)!})+(\frac{3!}{0!(3-0)!} \times \frac{8!}{4!(8-4)!})+(\frac{5!}{4!(5-4)!} \times \frac{8!}{0!(8-0)!})+(\frac{5!}{3!(5-3)!} \times \frac{8!}{1!(8-1)!})+(\frac{5!}{2!(5-2)!} \times\frac{8!}{2!(8-2)!})+(\frac{5!}{1!(5-1)!} \times \frac{8!}{3!(8-3)!})}{\frac{16!}{4!(16-4)!}}

= 0.5357

Hence The probability that the committee will consist of 1 from each type of monster is 0.1318 and Suppose that the Pokemon refuse to be on the same committee as a the Trolls.So,the probability that this type of committee is formed is 0.5357          

4 0
3 years ago
The upper quartile for the data set given below is <br> . 14, 8, 23, 9, 11, 27, 22, 3, 17, 12, 29
sdas [7]
The upper quartile is 23

6 0
3 years ago
A baby gains 11 pounds in its first year of life. The baby gained 4 1/4 pounds during the first four months and 3 1/2 pounds in
Ede4ka [16]

Answer:

3.25 pounds

Step-by-step explanation:

x + 4 (1/2) + 3 (1/2) = 11

x + 4.25 + 3.5 = 11

x + 7.75 = 11

x = 11 - 7.75

x = 3.25 pounds

8 0
3 years ago
I'm a bit confused with simplifying a squared fraction. Can you explain to me how I do it?
Margaret [11]

Answer:

\frac{\sqrt{6} }{3}

Step-by-step explanation:

\sqrt{\frac{2}{3} }

\frac{\sqrt{2} }{\sqrt{3} }

Multiply by \frac{\sqrt{3} }{\sqrt{3} } to simplify

\frac{\sqrt{2} }{\sqrt{3} }*\frac{\sqrt{3} }{\sqrt{3} }

\sqrt{2} *\sqrt{3} =\sqrt{6}

\sqrt{3} *\sqrt{3} =3

Therefore, the final answer would be:

\frac{\sqrt{6} }{3}

7 0
4 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
dalvyx [7]

Matching each equation of the plecewise function represented in the graph will be:

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<h3>How to illustrate the information?</h3>

It should be noted that a domain simply means the set of inputs that are accepted by the function.

In this case, the equation of the piecewise function represented is given.

The graph is attached.

Learn more about equations on:

brainly.com/question/2972832

#SPJ1

7 0
2 years ago
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