Answer: There are 177100 possible groups.
Step-by-step explanation:
Given: Total employees = 25
Number of employees wants to choose = 6
The combination of n things taken r at a time is given by:-

Put n = 25 and r= 6, we get

Hence, there are 177100 possible groups.
Answer:
Let us say the domain in the first case, has the numbers. And the co-domain has the students, .
Now for a relation to be a function, the input should have exactly one output, which is true in this case because each number is associated (picked up by) with only one student.
The second condition is that no element in the domain should be left without an output. This is taken care by the equal number of students and the cards. 25 cards and 25 students. And they pick exactly one card. So all the cards get picked.
Note that this function is one-one and onto in the sense that each input has different outputs and no element in the co domain is left without an image in the domain. Since this is an one-one onto function inverse should exist. If the inverse exists, then the domain and co domain can be interchanged. i.e., Students become the domain and the cards co-domain, exactly like Mario claimed. So, both are correct!
Answer:
The expected number of adult workers with a high school diploma is 4 out of 10
Step-by-step explanation:
4 out of 10 = 40%
12,000 pounds, 1 ton = 2000 pounds
Answer:
Th computed value of the test statistic is 3.597
Step-by-step explanation:
The null and the alternative hypothesis is as follows:
Null Hypothesis:
the population correlation coefficient is equal to zero
the population correlation coefficient is not equal to zero
The test statistics for Pearson correlation coefficient is thus computed as :

where;
r = correlation coefficient = 0.60
n = sample size = 25
So;



t = 3.597
Comparing to a critical value of t (23 degrees of freedom two-tailed value) = 2.069
Decision Rule:
Since computed value of t is greater than the critical value of t; We reject the null hypothesis and accept the alternative hypothesis.
Conclusion:
We conclude that the population correlation coefficient significantly differs from 0 at 5% (0.05) level of significance.