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sesenic [268]
3 years ago
8

Mia bicycles every day. Based on the graph, if Mia rides for 1.5 hours, how many miles does she bike?

Mathematics
1 answer:
Fudgin [204]3 years ago
3 0

Answer:

ITS C IT IS C!!!!!!!

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8,128 in expanded form no spaces
Taya2010 [7]

Haii

Step-by-step explanation:

8000+100+20+8 = 8,128

How to make expanded form:

<em>Its easy! all that must be done is that you break down the number like if you had a number 5091 this is how you break it down 5000 + 90 + 1. Breaking numbers down makes it easier to solve and you will be amazingg at math in no time!</em>

3 0
2 years ago
Read 2 more answers
X 5.2.19
Semmy [17]

Answer:

Step-by-step explanation:

y = ax² + bx + c

Plug the points into the equation to get a system of 3 equations with 3 unknowns a, b, and c.

-27 = 4a - 2b + c

-42 = 9a + 3b + c

-12 = a + b + c

(a,b,c) = (-4,1,-9)

y = -4x² + x - 9

7 0
2 years ago
Plz help me out with this and do show work I will be waiting.... btw u will be marked brainliest!!!!!! Fast plz
pychu [463]

Answer:

x=16°

Step-by-step explanation:

5*x-30=2*(x+18)

For the second, I'd say it is:

5*x-30=2*x+18  

Let's solve both.  

5*x-30=2*(x+18)

5x-30=2x+36

3x=66

x=22  

5*x-30=2*x+18

3x+48

x=16°

8 0
3 years ago
Write down the solution set for x&lt;3 in the set of natural numbers.
Gre4nikov [31]

Answer:

domain:{ [3, ∞], int}

Step-by-step explanation:

this is every possible number that is an integer, so domain:{ [3, ∞], int}

note that the format may be different

4 0
2 years ago
Read 2 more answers
Find the directional derivative of f(x,y,z)=2z2x+y3f(x,y,z)=2z2x+y3 at the point (−1,4,3)(−1,4,3) in the direction of the vector
Feliz [49]

f(x,y,z)=2z^2x+y^3

f has gradient

\nabla f(x,y,z)=2z^2\,\vec\imath+3y^2\,\vec\jmath+4xz\,\vec k

which at the point (-1, 4, 3) has a value of

\nabla f(-1,4,3)=18\,\vec\imath+48\,\vec\jmath-12\,\vec k

I'm not sure what the given direction vector is supposed to be, but my best guess is that it's intended to say \vec u=15\,\vec\imath+25\,\vec\jmath, in which case we have

\|\vec u\|=\sqrt{15^2+25^2}=5\sqrt{34}

Then the derivative of f at (-1, 4, 3) in the direction of \vec u is

D_{\vec u}f(-1,4,3)=\nabla f(-1,4,3)\cdot\dfrac{\vec u}{\|\vec u\|}=\boxed{\dfrac{294}{\sqrt{34}}}

4 0
3 years ago
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