Answer:
where is question ???
Step-by-step explanation:
Answer:
सॉरी भाई जल्द ही देखिये अलविदाIl existe de nombreux exemples de portfolios d’artistes en ligne. Trouvez-en un et partagez un lien vers celui-ci. En vous basant sur le portfolio, écrivez quelques phrases évaluant l'artiste. S'il y a les réponses d'autres élèves sur le forum de discussion, examinez-les et voyez si vous êtes d'accord ou pas d'accord avec leur opinion sur le travail des artistes.
We want to find miles per hour.
Speed is distance over time.
So take 10 miles (distance) / 3 hours (time)
This is the same as 10/3.
10/3 = 3 and 1/3
Therefore, the girl is going 3 and 1/3 miles per hour.
.503 is written as a decimal.
You move the dot left 2 times
Solution :
Let
and
represents the proportions of the seeds which germinate among the seeds planted in the soil containing
and
mushroom compost by weight respectively.
To test the null hypothesis
against the alternate hypothesis
.
Let
denotes the respective sample proportions and the
represents the sample size respectively.
![$\hat p_1 = \frac{74}{155} = 0.477419](https://tex.z-dn.net/?f=%24%5Chat%20p_1%20%3D%20%5Cfrac%7B74%7D%7B155%7D%20%3D%200.477419)
![n_1=155](https://tex.z-dn.net/?f=n_1%3D155)
![$p_2=\frac{86}{155}=0.554839](https://tex.z-dn.net/?f=%24p_2%3D%5Cfrac%7B86%7D%7B155%7D%3D0.554839)
![n_2=155](https://tex.z-dn.net/?f=n_2%3D155)
The test statistic can be written as :
![$z=\frac{(\hat p_1 - \hat p_2)}{\sqrt{\frac{\hat p_1 \times (1-\hat p_1)}{n_1}} + \frac{\hat p_2 \times (1-\hat p_2)}{n_2}}}](https://tex.z-dn.net/?f=%24z%3D%5Cfrac%7B%28%5Chat%20p_1%20-%20%5Chat%20p_2%29%7D%7B%5Csqrt%7B%5Cfrac%7B%5Chat%20p_1%20%5Ctimes%20%281-%5Chat%20p_1%29%7D%7Bn_1%7D%7D%20%2B%20%5Cfrac%7B%5Chat%20p_2%20%5Ctimes%20%281-%5Chat%20p_2%29%7D%7Bn_2%7D%7D%7D)
which under
follows the standard normal distribution.
We reject
at
level of significance, if the P-value
or if ![|z_{obs}|>Z_{0.025}](https://tex.z-dn.net/?f=%7Cz_%7Bobs%7D%7C%3EZ_%7B0.025%7D)
Now, the value of the test statistics = -1.368928
The critical value = ![\pm 1.959964](https://tex.z-dn.net/?f=%5Cpm%201.959964)
P-value = ![$P(|z|> z_{obs})= 2 \times P(z< -1.367928)$](https://tex.z-dn.net/?f=%24P%28%7Cz%7C%3E%20z_%7Bobs%7D%29%3D%202%20%5Ctimes%20P%28z%3C%20-1.367928%29%24)
![$=2 \times 0.085667$](https://tex.z-dn.net/?f=%24%3D2%20%5Ctimes%200.085667%24)
= 0.171335
Since the p-value > 0.05 and
, so we fail to reject
at
level of significance.
Hence we conclude that the two population proportion are not significantly different.
Conclusion :
There is not sufficient evidence to conclude that the
of the seeds that
with the percent of the
in the soil.