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Contact [7]
3 years ago
13

Given the system y > -2 x + y < 4

Mathematics
1 answer:
katen-ka-za [31]3 years ago
7 0

1. Points that lie on the intersection area of the inequalities are solutions.

For example (0,2), (-4,4), (2,-1), (-8,0) and all others which lie in this area.

2 Not solutions are points that are on the lines (because we have signs > and <, not ≤ and ≥), or on the areas that are not intercepted. For example, (6,2), (2,2), (2,-4),(-6,-2).

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A bus entered the freeway and traveled at a constant speed of 80 mph. Two hours later a second bus followed the first bus, enter
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It will take about 15-20 Minutes to catch up to that bus.

Step-by-step explanation:

65+ 20= 85 so its a tad bit over but it works.

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During a debate Bonnie used 9 minutes to present her opinion 6 minutes to rebut the opposing opinion and 5 minutes to summarize
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she spent like 40% of her time easy

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Read 2 more answers
Can someone please help me with this geometry question
goldenfox [79]

Answer:

A. q = 39

Step-by-step explanation:

Since the lines are parallel, their sides will be proportional,

So,

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=> \frac{60}{40} = \frac{q}{26}

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7 0
2 years ago
PLEASE HELP WILL MARK BRAINLIEST
Sholpan [36]

Answer: Choice D

b greater-than 3 and StartFraction 2 over 15 EndFraction

In other words,

b > 3 & 2/15

or

b > 3\frac{2}{15}\\\\

========================================================

Explanation:

Let's convert the mixed number 2 & 3/5 into an improper fraction.

We'll use the rule

a & b/c = (a*c + b)/c

In this case, a = 2, b = 3, c = 5

So,

a & b/c = (a*c + b)/c

2 & 3/5 = (2*5 + 3)/5

2 & 3/5 = (10 + 3)/5

2 & 3/5 = 13/5

The inequality 2 \frac{3}{5} < b - \frac{8}{15}\\\\ is the same as \frac{13}{5} < b - \frac{8}{15}\\\\

---------------------

Let's multiply both sides by 15 to clear out the fractions

\frac{13}{5} < b - \frac{8}{15}\\\\15*\frac{13}{5} < 15*\left(b - \frac{8}{15}\right)\\\\39 < 15b-8\\\\

---------------------

Now isolate the variable b

39 < 15b-8\\\\15b-8 > 39\\\\15b > 39+8\\\\15b > 47\\\\b > \frac{47}{15}\\\\b > \frac{45+2}{15}\\\\b > \frac{45}{15}+\frac{2}{15}\\\\b > 3+\frac{2}{15}\\\\b > 3\frac{2}{15}\\\\

Side note: Another way to go from 47/15 to 3 & 2/15 is to notice how

47/15 = 3 remainder 2

The 3 is the whole part while 2 helps form the fractional part. The denominator stays at 15 the whole time.

7 0
3 years ago
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