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zaharov [31]
3 years ago
9

Can anyone help with these answers

Mathematics
1 answer:
cricket20 [7]3 years ago
6 0
Um this is not middle school wow I'm shocked
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How does the sample size affect the validity of an empirical​ argument?
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When you say empirical argument, it means facts gathered and concluded through a series of experimentation and reliable data gathered and not through theory or speculation.

Therefore, a sample size can greatly affect the validity of an empirical argument once proven inaccurate because what we want to see in an empirical argument is the clear-cut reality of what the researchers gathered through meticolous experimentation and not otherwise.

300ml of ethanol is not the same as 300L of ethanol and 2 grams of salt is not 2 kilos of salt. However, if it can be explained thoroughly that a sample size is just a fraction representation of the original, it is wise to create a control subject to compare the data  and make it more reliable. Say for example, you wouild like to compare the sun and the earth, make sure to make the models realistically proportional in your miniature globe models.
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If I'm putting £100 a month into a fund that has 13.03% annual interest annually for 48 years, what's the the total??
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Let omega be a complex number such that omega^3 = 1. Find all possible values of {1}{1 + \omega} + {1}{1 + \omega^2}. Enter all
Norma-Jean [14]

Answer:

1 is Answer.

Step-by-step explanation

\frac{1}{1+omega^{2} } + \frac{1}{1+omega }\\

= \frac{(-1)*(omega + 1)}{omega^{2}  }

As we know that ω²+ω+1=0

Thus putting in above equation, we get

= \frac{1}{(-1)*omega } + \frac{1}{(-1)*omega^{2}  }

Rearranging and simplifying:

= \frac{-1}{omega } + \frac{-1}{omega^{2}  }

= \frac{(-1)*(omega + 1)}{omega^{2}  }

= \frac{(-1)*(- omega^{2} )}{omega^{2}  }

= 1 Answer

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3 years ago
Given that the following statement is true
Makovka662 [10]

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C IS THE ANS COS ALL POLYGONS ARE CLOSED AND IF IT NOT CLOSED IT NOT A POLYGON

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2 years ago
If (6y − 11)(6y 11) = ay^2 − b, what is the value of a? the value of a is ____________.
Triss [41]
(6y - 11)(6y + 11) = ay² - b    |use (a - b)(a + b) = a² - b²

(6y)² - 11² =ay² - b

36y² - 121 = ay² - b    |add b to both sides

ay² = 36y² - 121 + b        |divide both sides by y² ≠ 0

a = (36y² - 121 + b)/y²

\boxed{a=\dfrac{36y^2-121+b}{y^2}}
7 0
3 years ago
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