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Gre4nikov [31]
3 years ago
8

Box A contains 2 red and 2 green balls and box B contains 1 red and 2 green balls. A box is selected at random and then a ball i

s selected at random and it's color noted. If the ball is green, what is the probability that Box B was selected? What is the answer and how would I solve it?
Mathematics
1 answer:
serious [3.7K]3 years ago
5 0
The answer is 1/2. I think that since the question is about Box B , only boxes will be taken into consideration. Since the total number of boxes are two and box b is one ,the probability of the box being B is 1/2. 
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Galina-37 [17]

Answer:

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Step-by-step explanation:

To determine the 14th term of the geometric sequence that begins with 10, 40 and 160, knowing that each number is multiplied by 4, the following calculation must be performed, taking into account that the initial number (10) is multiplied by 4, and that said number must be potentiated 13 times to obtain the 14th term:

10 x (4 ^ 13) = X

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3 years ago
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X - 10 = 25
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gladu [14]

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Step-by-step explanation:

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gogolik [260]

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Given:

an =  \frac{an - 1}{4}  - 2

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Therefore, the first three terms of the sequence defined by the recursive formula are 2, -7/2 and -3/2

Learn more about sequence:

brainly.com/question/6561461

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EleoNora [17]
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