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Sedaia [141]
2 years ago
8

Which set of points on the graph represents equivalent ratios?

Mathematics
1 answer:
Elenna [48]2 years ago
8 0

Answer:c,d,f I think

Step-by-step explanation:

You might be interested in
The price of a coat increased from $78 to $92. What is the price increase percentage?
svetlana [45]

Answer:

18%

Step-by-step explanation:

Percent change can be found using the following formula:

\frac{original-new}{original}*100

Original represents the initial cost where new represents the new cost.  We multiply the answer by 100 to get the percentage:

\frac{92-78}{78}*100 = 18%

6 0
3 years ago
How to solve this.im stuck in this question for 20 mins. Plzz answer
Alik [6]

Answer:

Find the minimum or maximum value of the function g (I) = -3x^2 - 6x + 5. Describe the domain and range of the function, and where the function is increasing and decreasing. > -1 all real numbers The function The maximum value is I < 0 The domain is and the range is right of I left -1 is increasing to the of I= and decreasing to the 0 12 :: yo y0 :: 8 :: IS-1 :: -1 :: 0 :: I> 0 :: 1 :: 8 :: < 0 :: left :: all real numbers :: y -8 :: y < 8 :: y8​

Step-by-step explanation:

4 0
2 years ago
Please someone help me out on this
valentinak56 [21]

Answer:

I think it is C

Step-by-step explanation:

   

im  sorry if i am wrong    

6 0
2 years ago
Read 2 more answers
64-144a+108a^2-27a^3​
solmaris [256]

the answer for this question is 64-144a+108a^2-27a^3

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%2F7%7D%7B7%5Csqrt%7B10%7D%2F2%20%7D" id="TexFormula1" title="\frac{3/7}{7\sqrt{10}
VashaNatasha [74]

Multiply the numerator and denominator by 7×2 = 14 to eliminate the denominators of those fractions:

\dfrac{\dfrac37}{\dfrac{7\sqrt{10}}2}\times\dfrac{14}{14}=\dfrac{3\times2}{7\sqrt{10}\times7}=\dfrac6{49\sqrt{10}}

Rationalize the denominator by multiplying both numerator and denominator by √10:

\dfrac6{49\sqrt{10}}\times\dfrac{\sqrt{10}}{\sqrt{10}}=\dfrac{6\sqrt{10}}{49(\sqrt{10})^2}=\dfrac{6\sqrt{10}}{49\times10}=\dfrac{6\sqrt{10}}{490}

Lastly, cancel the common factor of 2 in both the numerator and denominator (which comes from 6 = 2×3 and 490 = 2×245):

\dfrac{6\sqrt{10}}{490}=\dfrac{3\sqrt{10}}{245}}

8 0
2 years ago
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