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liberstina [14]
3 years ago
11

The equilibrium system N2O4(g) 2NO2(g) was established in a 1.00 liter vessel. Upon analysis the following information was found

: [NO2] = 0.5 M; [N2O4] = 0.025 M. Calculate the numerical value for the Keq of the N2O4 2NO2 system.
Chemistry
1 answer:
Phoenix [80]3 years ago
7 0
The numerical  value  for the  Keq of  the N2O4 ⇔  2NO2  is  10 M

 calculation
Keq =  (  concentration NO)^2/ (  concentration  of N2O4)


Keq=  (0.5 )^2/0.025  =  10 M


The power of  NO2  is taken as  2  as  value  2  is  is the one in front of  No2 in equilibrium  equation
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