Answer:
0.924 g
Explanation:
The following data were obtained from the question:
Volume of CO2 at RTP = 0.50 dm³
Mass of CO2 =?
Next, we shall determine the number of mole of CO2 that occupied 0.50 dm³ at RTP (room temperature and pressure). This can be obtained as follow:
1 mole of gas = 24 dm³ at RTP
Thus,
1 mole of CO2 occupies 24 dm³ at RTP.
Therefore, Xmol of CO2 will occupy 0.50 dm³ at RTP i.e
Xmol of CO2 = 0.5 /24
Xmol of CO2 = 0.021 mole
Thus, 0.021 mole of CO2 occupied 0.5 dm³ at RTP.
Finally, we shall determine the mass of CO2 as follow:
Mole of CO2 = 0.021 mole
Molar mass of CO2 = 12 + (2×16) = 13 + 32 = 44 g/mol
Mass of CO2 =?
Mole = mass /Molar mass
0.021 = mass of CO2 /44
Cross multiply
Mass of CO2 = 0.021 × 44
Mass of CO2 = 0.924 g.
Answer:
CL
because cleetus will rule the world
The choices can be found elsewhere and as follows:
<span>A. 0.3
B. 3.9
C. 8.4
D. 11.7
</span>
I believe the correct answer is option B. <span>The pH of apple juice ranges from 3.35 to 4, which indicates it is on the acidic side of the pH scale. Hope this answers the question. Have a nice day.</span>
<h3>
Answer:</h3>
0.248 g
<h3>
Explanation:</h3>
<u>We are given;</u>
- Time as 40 minutes
- Original amount of N-13
We are required to calculate the amount left after decay.
- We need to know the half life of N-13 first;
- Half life of N-13 is 9 minutes 58 seconds (9.965 minutes0
We are going to use the formula;
- Remaining amount = Original amount × 0.5^n
That is; N = N₀ × 0.5^n , where n is the number of half lives.
n = 40 minutes ÷ 9.965 minutes
= 4.014
Therefore;
N = 4 g × 0.5^4.014
= 0.248 g
Therefore, the mass of Nitrogen-13 that will be left is 0.248 g
