Answer: New moon!
Explanation: So if your saying lunar eclips it would be new moon becuase we have full moons all the time that means lunar eclipses all the time soo it would be new moon
Answer:

Explanation:
Hello there!
In this case, according to the given information, it possible for us to realize that this problem is solved via the ideal gas equation:

By which we solve for n (moles) as shown below:

Then, we plug in the given pressure, volume and temperature (in K) to obtain:

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The value of Kb of the unknown amine is 3.22 x 10^-4.
Weak electrolytes:
The compound which do not dissociate completely when added to the aqueous solution are called weak electrolytes. The electrolyte and its ions exists in equilibrium. In case of weak base, the equilibrium constant is expressed as Kb.
Calculations:
Step 1:
The percentage of amine ionized at equilibrium is 2.2%.
NH3 + H2O ------> NH4+ + OH-
The concentration of conjugate acid at equilibrium is calculated as:
2.2 = (x/0.65) x 100
x = 0.0143 M
Step 2:
The equilibrium constant (Kb) is calculated as:
Kb = x^2/0.65 - x
= (0.0143)^2/(0.65 - x)
= 3.22 x 10^-4
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The half-life of the reaction is 101.9 min
<h3>First order reaction </h3>
When a reaction's pace and reactant concentration are inversely correlated, the process is known as a first-order reaction. To put it another way, the reaction rate doubles when the concentration does. One or two reactants can be present in a first-order reaction, as in the case of the decomposition process.
<h3>The half-life of first-order reaction:-</h3>
The amount of time it takes for the initial concentration of the reactant(s) to decrease by half is known as the half-life of a chemical reaction (abbreviated as "t1/2").
<h3 /><h3>Calculation:-</h3>
a→b
25% reacted means 75% remains
t=42 min
Rate constant
k=(2.303/t)(log a/a-x)
k=(2.303/42)(log 100/100-25 )
k=(0.054) (log 100/75)
k=(0.054)(0.1249)
k=0.0068 per min
half life
t1/2=(0.693/k)
=(0.693/0.0068)
=101.9 min
Learn more about first order reaction here :-
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