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gizmo_the_mogwai [7]
3 years ago
11

How do I do this? I'm not good with math

Mathematics
2 answers:
Alenkasestr [34]3 years ago
8 0
Slope intercept form formula is y=my+b. The b is your coefficient which does not move. This is where you would start on a graph on the y intercept. The b would be 30 because that is the number that will never change (your coefficient). The m is your slope and your x is how many times you will be taking the lessons. Your m will be 25 because per is a word you use for slope. The y just stays y. Your equation will be y=25x+30. For the second part you want to do y=25(6)+30. 25 multiplied by 6 is 150 and 150 added to your coefficient 30 is 180. A $200 gift card will pay for it. In the end $20 will be left.
sattari [20]3 years ago
4 0
1)y=25x+30
2) Yes 
3) 20$ left over
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At the city museumy child admission is and admission is $9.30. On Monday four times as many adult tickets as child tickets were
Scilla [17]

<em><u>Question:</u></em>

At the city museum, child admission is $5.80 and adult admission is $9.30. On Monday, four times as many adult tickets as child tickets were sold, for a total sales of $1548.00. How many child tickets were sold that day?

<em><u>Answer:</u></em>

36 child tickets were sold

<em><u>Solution:</u></em>

Given that,

Cost of 1 child admission = $ 5.80

Cost of 1 adult admission = $ 9.30

Let "c" be the number of child tickets sold

Let "a" be the number of adult tickets sold

On Monday, four times as many adult tickets as child tickets were sold

Number of adult tickets sold = four times the number of child tickets

Number of adult tickets sold = 4(number of child tickets sold)

a = 4c ----- eq 1

They were sold for a total sales of $ 1548.00

number of child tickets sold x Cost of 1 child admission + number of adult tickets sold x Cost of 1 adult admission = 1548.00

c \times 5.80 + a \times 9.30 = 1548

5.8c + 9.3a = 1548  ---- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "c" and "a"

Substitute eqn 1 in eqn 2

5.8c + 9.3(4c) = 1548

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